Find the 27th term of the arithmetic sequence 15, 17.25, 19.5, 21.75,...

Mathematics

2 answers:

lawyer [7]3 years ago

7 0

Answer:

Step-by-step explanation:

Find the Pattern -

The Pattern in the sequncesequence above would +2.25, so I assume the answer would be 73.5.

Fynjy0 [20]3 years ago

3 0

Answer:

The 27th term is 73.5.

Step-by-step explanation:

We want to find the 27th term of the arithmetic sequence:

15, 17.25, 19.5, 21.75, ...

We can write a direct formula. Recall that the direct formula for an arithmetic sequence is given by:

$x_n=a+d(n-1)$

Where a is the initial term and d is the common difference.

From the sequence, we can see that our initial term a is 15.

To find the common difference, subtract a term and its previous term. Thus, the common difference will be:

$d=17.25 - 15 = 2.25$

Thus, our direct formula is:

$x_n=15+2.25(n-1)$

To find the 27th term, let n = 27. Substitute and evaluate:

$\displaystyle \begin{aligned} x_{27} &=15+2.25((27)-1) \\ &= 15+2.25(26) \\&= 15+58.5 \\ &= 73.5\end{aligned}$

Thus, the 27th term is 73.5.

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An earthquake measuring 6.4 on the Richter scale struck Japan in July 2007, causing extensive damage. Earlier that year, a minor

a_sh-v [17]

Answer:

Step-by-step explanation

The earthquake measures 6.4 on the Richter scale which struck Japan in Jullu 2007 and caused and extensive damage. Earlier that year, a minor earthquake measuring 3.1 in the Richter scale has stroked in parts of Pennsylvania.

Fomular:

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Consider that M1 be the magnitude Japanese earthquake and M2 be the magnitude of the Pennsylvania earthquake and L1 be the intensity of the Japanese earthquake and L2 the intensity of the Pennsylvania earthquake.

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3 0

3 years ago

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Ksivusya [100]

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