System: x + y = 44; x = 2y + 2
Solve with substitution: x = 30; y = 14
x + y = 44
x = 2y + 2
Substitute 2y + 2 for x
2y + 2 + y = 44
3y + 2 = 44
Subtract 2 on both sides.
3y = 42
y = 14
Now substitute back in.
x + 14 = 44
Subtract 14 on both sides.
x = 30
Answer:
It lies between 5 and 6
Step-by-step explanation:
Two consecutive numbers are numbers that come after each other:
x , x + 1 are consecutive numbers.
3 \sqrt{3} = 3√3 = 5.19615242271
Therefore, from the above calculation, we can see that square root of 3 is a number that is between consecutive numbers 5 and 6
P(x) = 2x² - 4xq(x) = x - 3
To find the answer, we plug q(x) into p(x):
p(q(x)) = 2(x - 3)² - 4(x - 3)p(q(x)) = 2(x² - 6x + 9) - 4x + 12p(q(x)) = 2x² - 12x + 18 - 4x + 12p(q(x)) = 2x² - 16x + 30
The third option is correct.
