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LUCKY_DIMON [66]
3 years ago
6

Find the distance in the coordanite plane between the two points and show ur work

Mathematics
1 answer:
Alexxandr [17]3 years ago
6 0
Number 1 is 10 units
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Use the differential equation given by dy/dx=xy/3, y&gt;0<br><br> complete the table of values
melisa1 [442]
The \dfrac{\mathrm dy}{\mathrm dx} row is filled by just plugging in the corresponding values of x and y into the ODE.

For example, when x=-1 and y=1, you have

\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{xy}3\implies\dfrac{\mathrm dy}{\mathrm dx}\bigg|_{x=-1,y=1}=\dfrac{(-1)(1)}3=-\dfrac13

and so on.
6 0
3 years ago
Peter has a coupon for 15% off the price of any item in a sporting good store he wants to buy a pair of sneakers that are priced
aniked [119]

Answer:

$31.44

Step-by-step explanation:

According to the word problem, Peter has a coupon for 15% OFF.

This means the price will reduce by 15%.

To solve this, first, change the percentage (15%) to decimal form.

To do this, divide the percentage by 100.

15 / 100 = 0.15.

0.15 is the decimal form of 15%.

Next, multiply the decimal form of the percentage by the price.

36.99 x 0.15 = 5.5485

Lastly, subtract the product from the original price.

36.99 - 5.5485 = 31.4415

In this case, the product goes above the hundredths place.

So we must round 31.4415 to the hundredths place.

31.4415 ≈ 31.44

Therefore, the sneakers are $31.44 after the discount of 15%.

7 0
3 years ago
PLEASE HELP HELP ASAP ASAPP WILL GIVE 100 POINTS AND BRAINLEST! PLUS MY THANKS AND ADMIRATION PLEASE PLEASE!!
tatyana61 [14]

Answer:

First Picture ⇒ [B] <em>a = -2, b = 1, and c = -5</em>

<em>Second Picture ⇒ First step: Identify a = 1, b = 3, c = -4</em>

<em>                           </em>x=\frac{-3\pm \sqrt{3^2-4\cdot \:1\cdot \left(-4\right)}}{2\cdot \:1}

<em>                              </em>x=\frac{-3\pm 5\sqrt{25}}{2}

                           x=\frac{-3\pm \:5}{2}

                        x=\frac{-3+5}{2},\:x=\frac{-3-5}{2\c}

Third Picture ⇒ Missing Info

Fourth Picture ⇒ [A] x=-\frac{5}{2},\:x=-3

Fifth Picture ⇒ x=\frac{5\pm\sqrt{1} }{2}

Step-by-step explanation:

<em>-------------------------------------------------------------------------------------------------------------</em>

<em>Identify the a,b, and c-values for this equation:</em>

<em>y = -2x²  + x -5  </em>

<em>Quadratic Formula:</em>

<em>ax²+bx+c=0</em>

<em>−2x²+1x−5=0</em>

<em>a = -2, b = 1, and c = -5</em>

<em>-------------------------------------------------------------------------------------------------------------</em>

Order the steps for solving this equation using the quadratic formula.

x<em>²  + 3x - 4 = 0</em>

<em>Solving to see what are the steps:</em>

<em>First step: Identify a = 1, b = 3, c = -4</em>

<em />x=\frac{-3\pm \sqrt{3^2-4\cdot \:1\cdot \left(-4\right)}}{2\cdot \:1}

x=\frac{-3\pm 5\sqrt{25}}{2}

x=\frac{-3\pm \:5}{2}

x_1=\frac{-3+5}{2\cdot \:1},\:x_2=\frac{-3-5}{2\cdot \:1}

<em>-------------------------------------------------------------------------------------------------------------</em>

<em>Use the quadratic formula to find the solution set for 2x² + 15 = -11x.</em>

<em>Add 11x to both sides:</em>

<em>2x² + 15+11x = -11x+11x</em>

<em>Simplify</em>

<em>2x² + 11x+15 = 0</em>

<em>Now solve with quadratic formula..</em>

<em />x_{1,\:2}=\frac{-11\pm \sqrt{11^2-4\cdot \:2\cdot \:15}}{2\cdot \:2}

x_{1,\:2}=\frac{-11\pm \:1}{2\cdot \:2}

x_1=\frac{-11+1}{2\cdot \:2},\:x_2=\frac{-11-1}{2\cdot \:2}

x=-\frac{5}{2},\:x=-3

Hence, [A] x=-\frac{5}{2},\:x=-3

<em>-------------------------------------------------------------------------------------------------------------</em>

<em>Suppose you are solving a quadratic equation and this is your work so far...</em>

<em>x  ²  - 5x + 6 = 0</em>

<em>Thus, we have:</em>

<em />x=\frac{-\left(-5\right)\pm \sqrt{\left(-5\right)^2-4\cdot \:1\cdot \:6}}{2\cdot \:1}

x=\frac{-\left(-5\right)\pm \:1}{2\cdot \:1}

x=\frac{5\pm\sqrt{1} }{2}

x_1=\frac{-\left(-5\right)+1}{2\cdot \:1},\:x_2=\frac{-\left(-5\right)-1}{2\cdot \:1}

x=3,x=2

<em>-------------------------------------------------------------------------------------------------------------</em>

<u><em>Kavinsky</em></u>

6 0
2 years ago
Which of the following situations would best be modeled by a continuous relationship? A. The weight of a child over time. b. The
jeyben [28]

Answer:  The answer is (c) The temperature every morning at 8am.


Step-by-step explanation:  We are given four options and we are to select which situation among them can be best modelled by a continuous relationship.

A continuous relationship can be seen in a group of data where the values belonging to the group can take any value within a finite or infinite interval.

And a discrete relationship can be seen in a group of data where the values belonging to the group are distinct and separate.

We can easily see from the options that (a), (b) and (d) will fall in discrete relationship because the values here will be distinct and separate.

But, in option (c), the values of the temperature falls in a continuous relationship.

Thus, the correct option is (c).


6 0
3 years ago
Search
igor_vitrenko [27]

Answer:

25 minutes

Step-by-step explanation:

Just use logic here. If it takes him 15 minutes to run 3/5 of a bridge, that means it takes 5 minutes to run 1/5. To find the time it takes to run the whole bridge, multiply 5 by 5, which makes 25.

8 0
3 years ago
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