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shepuryov [24]
3 years ago
8

Salim had 24 homework problems.

Mathematics
1 answer:
lesantik [10]3 years ago
6 0

Answer:

so im guessing  the remainder of hw problems->

Step-by-step explanation:

24-7 =17 math problems left from doing some lunch

17-7= 10 math so its 10 math problems left

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Lines sand tare perpendicular. If the slope of line sis 5, what is the slope of<br> line t?
Sveta_85 [38]

Answer:

  -1/5

Step-by-step explanation:

Perpendicular lines have slopes that are the opposite reciprocal of one another.

The slope of line t is the opposite reciprocal of the slope of line s:

  slope of t = -1/(slope of s)

  slope of t = -1/5

6 0
3 years ago
What are a domain and range?
Nikolay [14]

Answer:

The domain and range of function is the set of all possible inputs and outputs of a function respectively.

The domain and range of a function y = f (x) is given as domain= {x ,x∈R }, range= {f (x), x∈Domain}.

The domain and range of any function can be found algebraically or graphically.

5 0
2 years ago
Locate the point on the line segment between A(3, -5) and B(13, -15) given that the point is 4/5 of the way from A to B. Show yo
SVETLANKA909090 [29]

Answer:

C ( 11 , -11 )

Step-by-step explanation:

Solution:-

We are given two points in the cartesian coordinate system as:

                   A ( 3 , -5 )              B ( 13 , -15 )

The point C lies on the line segment from A to B. The ratio of segment given is:

                              AC / AB = 4 / 5

To solve such type of problems. We will use vector equation of line AC.

To form a vector equation of line representing AB. We will first determine the direction vector ( d ) that is parallel to the line AB as follows:

                 d = OB - OA

                 d = < 13 , -15 > - < 3 , -5 >  

                 d = < 10 , -10 >

The fixed point on the line is taken. We will take point A. The vector equation of line from point A to point B is expressed as:

                < x , y > = OA + s*d

                < x , y > = < 3, -5 > + s* < 10 , -10 >  

The above equation satisfies all the points that lies on the line AB. To determine the coordinates of ( C ). We will plug in the appropriate value of parameter ( s ) and evaluate.

So point C is 4/5 th the magnitude of the distance AB from A. Hence, s = 4/5 as follows:

               < x , y > = < 3 , -5 > + ( 4/5 ) * < 10 , -10 >  

               < x , y > = < 3 , -5 > + < 8 , -8 >  

              < x , y > = < 11 , -11 >   ... Answer

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