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2 years ago

Help ASAP pleaseee lol

Mathematics

1 answer:

Julli [10]2 years ago

4 0

I’ve attached my table of what I’ve done

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If a×b×c=0 and a and b are integers greater than 10 what must equal c

myrzilka [38]

C is 0, since only multiplied by 0 will get 0, and the question defined that a and b not 0, so only c is 0

4 0

3 years ago

Read 2 more answers

Is y = 3/2x +5/4 and -2x+8y=-25 a solution

nekit [7.7K]

Answer: x=-35/10

y=-4

Step-by-step explanation:

y = 3/2x +5/4

-2x+8y=-25

--------------------

replace y in second equation with: y = 3/2x +5/4

-2x+8(3/2x+5/4)= -25

-2x+12x+10= -25

10x=-35

x=-35/10

x=-3.5

7+8y= -25

8y=-32

y=-4

7 0

3 years ago

Help please this is for my homework that is due to tomorrow!!

Murljashka [212]

The given polygons are similar

Step-by-step explanation:

By observing the given diagrams, we can see that the respective angles are congruent.

Two shapes are said to be similar if they have same shapes or one shape is created by uniformly increasing or decreasing the side of other.

For this purpose we find the scale factor of greater to smaller image, if the scale factor is same for each side then the two shapes are similar

So,

The scale factor is:

$\frac{EF}{AB} = \frac{3}{1} = 3\\\\\frac{FG}{BC} = \frac{9}{3} = 3\\\\\frac{GH}{CD} = \frac{15}{5} = 3\\\\\frac{EH}{AD} = \frac{21}{7} = 3$

We can see that the scale factor is same for all sides.

Hence,

The given polygons are similar

Keywords: Polygons, similarity

Learn more about polygons at:

#LearnwithBrainly

5 0

2 years ago

A landscape architect is designing a pool that has this top view<br>

denpristay [2]

Answer:

what view?

and whats the question?

Step-by-step explanation:

4 0

2 years ago

What are the roots to<br> the equation<br> 2x² + 6x-1=0?

lys-0071 [83]

Answer:

The roots of equations are as m = $\frac{-3}{2} + \frac{\sqrt{11} }{2}$ And n = $\frac{-3}{2} - \frac{\sqrt{11} }{2}$

Step-by-step explanation:

The given quadratic equation is 2 x² + 6 x - 1 = 0

This equation is in form of a x² + b x + c = 0

Let the roots of the equation are ( m , n )

Now , sum of roots = $\frac{ - b}{a}$

And products of roots = $\frac{c}{a}$

So, m + n = $\frac{ - 6}{2}$ = - 3

And m × n = $\frac{ - 1}{2}$

Or, (m - n)² = (m + n)² - 4mn

Or, (m - n)² = (-3)² - 4 ( $\frac{ - 1}{2}$ )

Or, (m - n)² = 9 + 2 = 11

I.e m - n = $\sqrt{11}$

Again m + n = - 3 And m - n = $\sqrt{11}$

Solving this two equation

(m + n) + ( m - n) = - 3 + $\sqrt{11}$

I.e 2 m = - 3 + $\sqrt{11}$

Or, m = $\frac{-3}{2} + \frac{\sqrt{11} }{2}$

Similarly n = $\frac{-3}{2} - \frac{\sqrt{11} }{2}$

Hence the roots of equations are as m = $\frac{-3}{2} + \frac{\sqrt{11} }{2}$ And n = $\frac{-3}{2} - \frac{\sqrt{11} }{2}$ Answer

6 0

3 years ago