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3 years ago

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The negative effects of a recession would be reduced by which fiscal policy decision?

1 answer:

Elis [28]3 years ago

3 0

Answer:

The negative effects of a recession would be reduced by which fiscal policy decision?

A. incurring a budget deficit which is used to retire debt held by the public

<h3>B. incurring a budget surplus and allowing that surplus to accumulate as idle Treasury balances</h3>

C. incurring a budget surplus, which is used to retire debt held by commercial banks

D. incurring a budget deficit by borrowing from the public and increasing expenditures

Step-by-step explanation:

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I need help!<br> Its not a real question im just practicting!

Firdavs [7]

Look here in a square which is what I imagine that drawing is all the angles are 90 degrees. A rectangle would be knowing two angles is know all of them one way or another so fix your work and you should know the answer

4 0

2 years ago

Read 2 more answers

A tarp is used to keep the infield of a baseball field from getting wet. The infield is a square. The corners of the square tarp

Dafna11 [192]

Answer:

<h2>a. 2,025 ft</h2><h2>b. 8,100 is a perfect square. </h2>

Step-by-step & explanation:

<em>It is a perfect square because if it wasn't, it wouldn't be equally a whole number when divided by 4 or 2,025 exactly on ALL 4 sides and when finding the root of 8,100 it's a perfect 90. As you should already know a perfect square has a given 90 degree angle.</em>

Tarp = 8,100 sq ft.

- anchored corners at the base.

- Square infield.

Well if there's 4 bases, divide 8,100 by 4.

8,100 / 4 = 2,025

One base to another base is 2,025 ft.

8 0

3 years ago

Matthew visited the fruits garden last weekend and helped farmers count the fruits. There were 10% more dragon fruits than passi

lara31 [8.8K]

Answer:

Step-by-step explanation:

let number of passion fruits=x

number of dragon fruits=x+10% of x

=x+0.1 x=(1+0.1)x=1.1 x

total number of fruits=x+1.1 x=(1+1.1)x=2.1 x

1.1x+60% of 1.1x+x+9% of x=2.1x+75

1.1 x+0.6 of 1.1 x+x+0.09 of x=2.1x+75

1.1x+0.66 x+x+0.09 of x =2.1x+75

2.1 x+0.75x-2.1 x=75

0.75 x=75

$\frac{75}{100}x =75\\x=75 \times \frac{100}{75} =100\\Originally ~total ~number~ of~ fruits=2.1x=2.1 \times100=210$

3 0

2 years ago

Read 2 more answers

Which is the completely factored form of 12x3 – 60x2 4x – 20? 4(3x2 – 1)(x – 5) 4x(3x2 1)(x – 5) 4x(3x2 – 1)(x 5) 4(3x2 1)(x – 5

Neporo4naja [7]

The factors of the polynomial are $\rm 4(3x^2 + 1)(x-5)$ .

<h3>Factorization;</h3>

Factorization is nothing but writing a number as the product of smaller numbers.

Given

Polynomial; $\rm 12x^3 - 60x^2 + 4x -20$

To find the factorization the polynomial equates the equation with zero following all the steps given below.

Then,

The factor of the polynomial is;

$\rm 12x^3 - 60x^2 + 4x -20\\\\ 12x^3(x-5)+4(x-5)\\\\(12x^3+4)(x-5)\\\\ 4(3x^2 + 1)(x-5)$

Hence, the factors of the polynomial are $\rm 4(3x^2 + 1)(x-5)$ .

To know more about factorization click the link given below.

brainly.com/question/17595467

4 0

2 years ago

Consider writing onto a computer disk and then sending it through a certifier that counts the number of missing pulses. Suppose

Furkat [3]

Answer:

a) 0.164 = 16.4% probability that a disk has exactly one missing pulse

b) 0.017 = 1.7% probability that a disk has at least two missing pulses

c) 0.671 = 67.1% probability that neither contains a missing pulse

Step-by-step explanation:

To solve this question, we need to understand the Poisson distribution and the binomial distribution(for item c).

Poisson distribution:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}
$

In which

x is the number of sucesses

$
e = 2.71828$ is the Euler number

$\mu$ is the mean in the given interval.

Binomial distribution:

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

Poisson mean:

$\mu = 0.2$

a. What is the probability that a disk has exactly one missing pulse?

One disk, so Poisson.

This is P(X = 1).

$P(X = 1) = \frac{e^{-0.2}*0.2^{1}}{(1)!} = 0.164
$

0.164 = 16.4% probability that a disk has exactly one missing pulse

b. What is the probability that a disk has at least two missing pulses?

$P(X \geq 2) = 1 - P(X < 2)$

In which

$P(X < 2) = P(X = 0) + P(X = 1)$

In which

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}
$

$P(X = 0) = \frac{e^{-0.2}*0.2^{0}}{(0)!} = 0.819$

$P(X = 1) = \frac{e^{-0.2}*0.2^{1}}{(1)!} = 0.164
$

$P(X < 2) = P(X = 0) + P(X = 1) = 0.819 + 0.164 = 0.983$

$P(X \geq 2) = 1 - P(X < 2) = 1 - 0.983 = 0.017$

0.017 = 1.7% probability that a disk has at least two missing pulses

c. If two disks are independently selected, what is the probability that neither contains a missing pulse?

Two disks, so binomial with n = 2.

A disk has a 0.819 probability of containing no missing pulse, and a 1 - 0.819 = 0.181 probability of containing a missing pulse, so $p = 0.181$

We want to find P(X = 0).

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{2,0}.(0.181)^{0}.(0.819)^{2} = 0.671$

0.671 = 67.1% probability that neither contains a missing pulse

8 0

3 years ago