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sasho [114]
3 years ago
8

As your sixteenth birthday approaches you are looking for ways to make money so you can buy a used car. Currently, you earn $10

a week for doing chores around the house. Your father realizes that you are trying to save up, and offers you the following deal. You can either be paid the $10, or you can pull two bills from a brown paper bag. In the bag there are two $1 bills, two $5 bills, and a $10 bill. For example, you might pull out a $1 bill followed by a $5 bill, and earn only $6. Or you might pull out the $10 bill followed by a $5 bill and earn $15. If you were given this option every week, what would be better for you to do in the long run? Is pulling two bills from the paper bag a great way to make money? Justify your answer​
Mathematics
1 answer:
Eduardwww [97]3 years ago
8 0

A. Personally if i was given these 2 options i would take the choice of drawing 2 bills from the bag per week.

B. Yes, i do not think pulling 2 bills from the bag is a good way to make money.

A. You could either get 10$ per week or you could get, 2$ 6$ 6$ 10$ 11$ 11$ 15$ 15$ now this depends largely on luck but logically 5 out of 9 times you will get 10 dollars or more so there is a higher chance you get more money from drawing money.

B. It is a good way to make money because 2/9ths of the time you will get 15$ and for every time you get 6$ you will get an equal amount of 15$ and you will get 21$ in the 2 weeks so it adds up, if you have bad luck or do this for a short amount of time then you could be losing out but if you have an average amount of luck then it will be worth the chance.

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The diagram below shows the rectangle PLUM.
Illusion [34]

Answer:

Area of rectangle PLUM = 75.00 square units

Step-by-step explanation:

Since diagonal of rectangle divides the rectangle into two equal triangles,

Therefore, area of the rectangle PLUM = 2× area of triangle PLM

By the mean proportional theorem,

In ΔPLM,

AP² = AM × AL

6² = AM × 8

AM = \frac{36}{8}

AM = 4.5 units

Area of PLM = \frac{1}{2}(\text{Base})(\text{height})

                     = \frac{1}{2}(ML)(AP)

                     = \frac{1}{2}(8 + 4.5)(6)

                     = 12.5 × 3

                     = 37.5 units²

Now area of rectangle PLUM = 2×37.5 = 75 units²

Therefore, area of the rectangle is 75.00 square units.

3 0
3 years ago
Find X, AB, BC, and AC if B is the midpoint of AC
Mkey [24]

Answer:

x=6, AB=61, BC=61, AC=122

Step-by-step explanation:

AB=BC \\ \\ 10x+1=8x+13 \\ \\ 2x=12 \\ \\ x=6 \\ \\ AB=BC=61 \\ \\ AC=122

4 0
1 year ago
What is the volume of the rectangular pyramid shown belown?
Anna35 [415]

9514 1404 393

Answer:

  168 cubic inches

Step-by-step explanation:

The formula for the volume of a pyramid is ...

  V = (1/3)Bh

where B is the area of the base, and h is the height.

The base is a rectangle, whose are is given by the formula ...

  A = LW

  A = (8 in)(7 in) = 56 in²

Then the pyramid volume is ...

  V = (1/3)(56 in²)(9 in) = 168 in³

The volume of the pyramid is 168 cubic inches.

7 0
3 years ago
Whats the surface area of the prism below,and please explain how you got the answer :)
nevsk [136]
Answer: 480 units^2



IN DEPTH EXPLANATION TO HELP YOU FOR FUTURE PROBLEMS:

Front:
b*h/2 = sa
12*5/2 = 30
Front = 30 units^2

Back:
b*h/2 = sa
12*5/2 = 30
Back = 30 units^2

Right:
w*l = sa
14*13 = 182 units^2
Right: 182 units*2
(figures out the length by using
pythagorean theorem)

Left:
w*l = sa
5*14 = 70 units^2
Left: 70 units^2

Bottom:
w*l = sa
12*14 = 168 units^2

ADD ALL THE UNITS:
168 + 70 + 182 + 30 + 30 = 480

4 0
3 years ago
I need to get the left side to equal the right side. Keeping the right side alone and not changing it.
likoan [24]

<u>To prove the trigonometric equation:</u>

\sin ^{3} x+\cos ^{3} x=(\sin x+\cos x)(1-\sin x \cos x)

RHS=(\sin x+\cos x)(1-\sin x \cos x)

We know that \sin^2x +\cos^2x=1, substitute this in place of 1.

       =(\sin x+\cos x)(\sin^2x +\cos^2x-\sin x \cos x)

Multiply each term of the first term with each term of the 2nd term.

       =\sin^3x + \sin x \cos^2x-\sin^2 x \cos x+\cos x \sin^2 x + \cos^3 x-\sin x\cos^2 x

Group like terms together.

       =\sin^3x +( \sin x \cos^2x-\sin x\cos^2 x)+(\cos x \sin^2 x-\sin^2 x \cos x) + \cos^3 x

       =\sin^3x +( 0)+(0) + \cos^3 x

       =\sin^3x + \cos^3 x

       = LHS

RHS = LHS

\sin ^{3} x+\cos ^{3} x=(\sin x+\cos x)(1-\sin x \cos x)

Hence proved.

7 0
3 years ago
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