But 37 is not a factor of 3, in fact it is a prime number so anything that is divisible by it (other than 1) will be a decimal. So, my friend here you have another person on this app telling you that it is not 3 and is in fact 3.2432 (;;;
Answer:
Correct option is
A
49m
The circumference of a circular field is 308m
Therefore, 2πr=308
⇒r=
2×22
308×7
⇒r=49m
Step-by-step explanation:
here you go
<span>Look at your table for a Z value of 1.55. The numbers on the far left column are your z values. See the 1.5 row, then move over to the 0.05 column to make it 1.55.
You'll see 0.9394.
That's the area under the normal curve from 1.55 to negative infinity.
But you wanted the area under the curve greater than 1.55.
Take 1-0.9394=0.0606.
You subtract from 1 because you know that the area under the whole curve is 1, so it gives you the area you need.</span>
Answer:
5.49779
Step-by-step explanation:
Answer:
Ebony need to compare ∠EFG and ∠ONM
Step-by-step explanation:
we know that
If two angles and the included side of one triangle are equal to the corresponding angles and side of another triangle, the triangles are congruent by ASA
In this problem
EF ≅ ON ----> the included side
To prove congruence by ASA, of triangles EFG and ONM, the corresponding angles of the included side must be congruent
The corresponding angles of the included side are
∠MON and ∠GEF
and
∠EFG and ∠CNM
so
∠MON ≅ ∠GEF ----> given problem
and
∠EFG ≅ ∠CNM
therefore
Ebony need to compare ∠EFG and ∠ONM
Both angles must be congruent, to prove that triangles EFG and ONM are congruent by ASA
