It’s a little complicated but here’s how it works:
Imagine a table with the intervals
0:4 , 4:6 , 6:7 , 7:10 , 10:13 (10 year intervals)
Then we have different rows
Class width: 4 , 2 , 1 , 3 , 3
Freq density: 0.2 , 0.5 , 1.2 , 0.7 , 0.3
So now calculate frequency where freq = class width * density
Freq: 0.8 , 1 , 3.6 , 2.1 , 0.9
So to find median find cumulative frequency
(Add all freq)
Cfreq = 8.4 now divide by 2 = 4.2
So find the interval where 4.2 lies.
0.8 + 1 = 1.8 + 3.6 = 5.6
So 4.2 (median) will lie in that interval 60-70 years.
Answer:
i) 24
ii) 4 girls, 3 boys
Step-by-step explanation:
The GCF is 24
96= 24*<u>4</u>
72= 24*<u>3</u>
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<u>I hope this helps!</u>
Answer:
y+2= -4(x-8)
Step-by-step explanation:
answer: I think the result is 12
Step-by-step explanation:
c(b+a)-a=
2(3+6)-6=
6+12-6= 12
To simplify the given equation, you want to combine like terms. Since both terms have x^8, we can add the coefficients and leave the x^8
3x^8-7x^8 (do 3-7)
=-4x^8 so the answer is C
Hope this helps
