To find the interquartile range, you will list the data that is presented in the stem and leaf plot.
Find the median of the data (30.5)
Find the median of the lower half and the median of the upper half.
Subtract these two values.
The data are <u>20</u>, 25, 30, 30, 31, 40, 41, <u>49</u>.
27.5 40.5
40.5-27.5 = 13
The interquartile range is 13.
1/12 I think I’m sorry if it isn’t
Answer:
a) 0.6435 radians
b) 80.1 feet/sec
Step-by-step explanation:
a) 75 = (50²/16)sin(theta)cos(theta)
sin(theta)cos(theta) = 0.48
2sin(theta)cos(theta) = 0.96
sin(2theta) = 0.96
2theta = 1.287002218
Theta = 0.6435011088 radians
b) 200 = (v²/16)sin(0.75)cos(0.75)
6416.072347 = v²
v = 80.10038918 feet/sec
Answer:
2
Step-by-step explanation:
Answer:
The other leg is 6 and the Hypotenuse is 6√2
Step-by-step explanation:
because it's a 45 45 90 the legs equal and the Hypotenuse is square root 2 times leg