Answer:
AECG
Step-by-step explanation:
1
sqrt(49) = 7
sqrt(a^2) = a
sqrt(b^2) = b
For every two variables you can take one out from under the root sign and thorough the other one away.
Answer: E
2
sqrt(36) = 6
sqrt(a^2) = a See comment for 1.
b must be left where it is. There is only 1 of them.
6asqrt(b)
Answer: A
3. sqrt(25) = 5
sqrt(b^2) = b
a must be left alone. There's only 1 of them.
5b sqrt(a)
answer: C
4
sqrt(81 a b)
sqrt(81) = 9
The variables must be left alone. There's only1 of them
9 sqrt(ab)
Answer G
Answer:
1,757,600,000
Step-by-step explanation:
company consists of 3 letters followed by 5 numbers how many different account numbers are possible if repetitions of letters and digits are allowed.
We have 26 lettrs and 10 digits
So, the possible out comes for each one of the letters = 26
And the possible out comes for each one of the numbers = 10
∵ repetitions of letters and digits are allowed.
So, the possible accounts are = 26³ * 10⁵ = <u>1,757,600,000</u>
Answer:
what is that
Step-by-step explanation:
roeeo
Log₄20-log₄ 45+log₄144=
log₄(20/45)+log₄144= (log_a b- log_a c=log_a (b/c) )
log₄[(20*144)/45]= (log_a b +log_a c=log_a (b*c) )
log₄(2880/45)=
log₄(64)=n ⇔ 4^n=64 (log_a x=n ⇔ a^n=x)
4^n=4³ ⇒n=3 (64=4*4*4=4³)
Answer: log₄20-log₄ 45+log₄144=3
Answer:
Therefore we can say that 98 boxes will be needed to hold all the paperweights.
Step-by-step explanation:
i) there are 1657 souvenir paperweights that need to be packed in boxes.
ii) each box will hold 17 paperweights
iii) therefore the number of boxes that will be needed are
= 
= 
= 97.471
iv) Therefore we can say that 98 boxes will be needed to hold all the paperweights.
