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sattari [20]
3 years ago
9

Please help on #21 I’ll mark you as brainliest if correct

Biology
2 answers:
Andru [333]3 years ago
8 0
The answer is J the desert. This mechanism is used to draw out long periods of time since the desert doesn’t receive as much rain as any other ecosystem.
Marina CMI [18]3 years ago
5 0

Answer:

I think the answer is J: desert.

Explanation:

In the grassland, rainforest, and swamp, it either rains frequently or is constantly surrounded by water.  However, deserts rarely get any water. Also, not many desert plants have leaves, but instead have very large stems, like cacti and large sage bushes. Therefore, the desert would be the most important habitat this could take place.

Pls mark brainliest if possible!!! Have a fantabulous day!!!

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The small intestine is ___ to the liver. (EX, Superior, Medial, Distal, Deep)
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Answer:

The small intestine is ___ to the liver. (Superior)

4 0
3 years ago
The more similar the DNA sequences of two species are, the more closely related the species are. Please select the best answer f
erica [24]
Alright my friend the answer to your question will be true let's put an example in to inform why it is alright so say you and your cousin look a like that's because the genetics are similar but not exactly the same
6 0
3 years ago
Is the general term for a grouping of organisms
olga nikolaevna [1]

Answer:

Classification of Living things

Explanation:

8 0
3 years ago
22. A plant geneticist is investigating the inheritance of genes for bitter taste (Su) and explosive rind (e) in watermelon (Cit
mylen [45]

Answer:

See the answer below

Explanation:

Using the formula for calculating Chi square (X^2):

X^2  =  \frac{(O - E)^2}{E} where O = observed frequency and E = expected frequency.

The observed frequencies for the four phenotypes are 88, 62, 62, and 81 respectively.

For the expected frequency, the phenotypes are supposed to assort in 9:3:3:1 according to Mendel ratio.

Hence, expected frequencies are calculated as:

phenotype (1) = 9/16 x 293 = 164.81

phenotype (2) = 3/16 x 293 = 54.94

phenotype (3) = 3/16 x 293 = 54.94

phenotype (4) = 1/16 x 293 = 18.31

The X^2 is calculated thus:

Phenotype            O               E                             X^2

  1                          88            164.81            \frac{(88 - 164.81)^2}{164.81} = 35.80

  2                          62             54.94            \frac{(62 - 54.94)^2}{54.94} = 0.91

  3                           62             54.94              \frac{(62 - 54.94)^2}{54.94} = 0.91

  4                            81              18.31               \frac{(81 - 18.31)^2}{18.31} = 214.64

Total X^2 = 35.80 + 0.91 + 0.91 + 214.64 = 252.26

To the nearest tenth = 252

Degree of freedom = n - 1 = 4- 1 = 3

X^2 tabulated  = 7.815

<em>The calculated </em>X^2<em> exceeds the critical value, hence, the null hypothesis is rejected. The two genes did not assort independently.        </em>

4 0
3 years ago
Which is a difference between animal populations in primary succession and secondary succession?
Agata [3.3K]
I believe it is A. Primary succession starts with plants and rocks.
8 0
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