60 60 and 60. Hope I helped!
There are
ways of pairing up any 2 members from the pool of 
contestants. Note that
so that
Answer:
The correct option is A
Step-by-step explanation:
The given expression is:
√10/4√8
We have to eliminate the √ from the denominator
4√8 = (2^3)^1/4
Multiply the whole expression by (2)^1/4
=(2)^1/4 * √10/ 2^(1/4)*(2^3)^(1/4)
= 2^(1/4) · 10^(2/4) / 2^1/4+3/4
=2^(1/4) · 10^(2/4) / 2^1+3/4
=2^(1/4) · 10^(2/4) / 2^4/4
=2^(1/4) · 10^(2/4) /2
=2^(1/4) · 100^(1/4) /2
=200^1/4 /2
= 4√200 /2
Thus the correct option is A....
The answer is C. 16/55 because P(Q and R) = P (Q) . P (R) (for independent events Q and R)
So, the prob. is 4/5 * 4/11 = 16/55 = D.
