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anyanavicka [17]
3 years ago
15

Jacob Sketched a floor plan for a new two room clubhouse . In his sketch each centimeter was equal to 1.5 feet . The largest roo

m on his clubhouse plan measured 6.2 cm by 7.4 cm. How many square feet would the actual room be? Round you answer to the nearest hundredth.
Mathematics
1 answer:
asambeis [7]3 years ago
6 0

Answer:

103.23 square feet

Step-by-step explanation:

Area of the largest room = length × width

Each centimeter was equal to 1.5 feet

7.4 cm = 1.5 × 7.4 = 11.1 feet

6.2 cm = 1.5 × 6.2 = 9.3 feet

Length = 11.1 feet

Width = 9.3 feet

Area of the largest room = length × width

= 11.1 feet × 9.3 feet

= 103.23 square feet

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Answer:

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Using chebyshev's theorem :

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\to |(x-\mu)|= |20.17-28.75|=8.58 and \sigma=4.44 \\\\so, \\k= \frac{ |(x-\mu)| }{\sigma}

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In point b)

\to (1- \frac{1}{k^2}) \times 100 \% =84\% \\\\\to (1- \frac{1}{k^2})=0.84 \\\\\to \frac{1}{k^2} =0.16 \\\\\to \frac{1}{k}=0.4\\\\ \to k=2.5 \\\\\to |(x-\mu)| \leq k \sigma  \\\\= |(x-\mu)|\leq 2.5 \times 4.44  \\\\  = |(x-\mu)|\leq 1.11 \\\\ =  (28.75\pm 11.1) \\\\\to \text{fares lies between}(17.65,39.85)

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\to 99.7 \% \\ lie \ between=28.75 \pm z(.03)\times \sigma \\\\ =28.75\pm 2.97 \times 4.44\\\\=(28.75\pm 13.1)\\\\=(15.65,41.85)\\

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x=20.17\\\\  z=-2 \\\\x=37.13\\\\ z=2\\\\\to P(20.17

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