Answer:
a. 
b. 
Step-by-step explanation:
a. 
A mixed fraction of the form 



b. 
A mixed fraction of the form 




Hence, the answer.
Answer:
y=-5/3x+20
Step-by-step explanation:
Let the equation of the required line be represented as ![\[y=mx+c\]](https://tex.z-dn.net/?f=%5C%5By%3Dmx%2Bc%5C%5D)
This line is perpendicular to the line ![\[y=\frac{3}{5}x+10\]](https://tex.z-dn.net/?f=%5C%5By%3D%5Cfrac%7B3%7D%7B5%7Dx%2B10%5C%5D)
![\[=>m*\frac{3}{5}=-1\]](https://tex.z-dn.net/?f=%5C%5B%3D%3Em%2A%5Cfrac%7B3%7D%7B5%7D%3D-1%5C%5D)
![\[=>m=\frac{-5}{3}\]](https://tex.z-dn.net/?f=%5C%5B%3D%3Em%3D%5Cfrac%7B-5%7D%7B3%7D%5C%5D)
So the equation of the required line becomes ![\[y=\frac{-5}{3}x+c\]](https://tex.z-dn.net/?f=%5C%5By%3D%5Cfrac%7B-5%7D%7B3%7Dx%2Bc%5C%5D)
This line passes through the point (15.-5)
![\[-5=\frac{-5}{3}*15+c\]](https://tex.z-dn.net/?f=%5C%5B-5%3D%5Cfrac%7B-5%7D%7B3%7D%2A15%2Bc%5C%5D)
![\[=>c=20\]](https://tex.z-dn.net/?f=%5C%5B%3D%3Ec%3D20%5C%5D)
So the equation of the required line is ![\[y=\frac{-5}{3}x+20\]](https://tex.z-dn.net/?f=%5C%5By%3D%5Cfrac%7B-5%7D%7B3%7Dx%2B20%5C%5D)
Among the given options, option 4 is the correct one.
Incomplete Question the complete Qs is
Which of the following is a correct equation for the line passing through the point (-2,1) and having slope m = 1/2?
a: y=1/2x+2
b: y=-2x+1/2
c: x-2y=-4
d: y-1=1/2(x+2)
Answer:
The Correct option is c. x-2y=-4
Therefore the correct equation for the line passing through the point (-2,1) and having slope m= 1/2 is

Step-by-step explanation:
Given:

point A(x₁, y₁)=(-2,1)
To Find:
Equation of Line =?
Solution:
Equation of a line passing through a points A( x₁ , y₁) and having slope m is given by the formula,
i.e equation in point - slope form
Now on substituting the slope and point A( x₁ , y₁) ≡ ( -2 , 1) we get
As required
Therefore the correct equation for the line passing through the point (-2,1) and having slope m= 1/2 is

Answer:
Alemania / Germany
Step-by-step explanation:
Clearly the text refers to Germany (Alemnia). Felipe will celebrate a holiday with his german family (familia alemana)