5/6-1/9=?/?-?/? =13/18

1 answer:

4 0

15/18 - 2/18 = 13/18

Find the least common multiple of 6 and 9. The LCM is 18. In order to get 18 on the denominator with 6, you have to multiply by 3 because 6 times 3 is 18. You have to multiply 3 to the numerator, so 5 times 3 is 15. Thus, the first fraction is 15/18. To get the second, you need to find what would get you 18 on the denominator with 9. You need 2, so 9 times 2 is 18. You have to multiply 2 to the numerator, so 1 times 2 is 2. Thus, the second fraction is 2/18.

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Read 2 more answers

If a number is chosen at random from the set {1, 2, 3, 4, . . ., 18}, what is the probability that the number chosen is a factor

choli [55]

Looking at the set, we are given 18 elements. 17 is prime; it has only two factors: 1 and 17, since 1•17=17. So, the question is really asking what is the probability the numbers 1 or 17 is chosen. As mentioned earlier, 17 is prime, so there are two possible choices: 1 and 17.

P (probability) = possible outcomes / total outcomes

It is important to note that these events are “or” events, meaning that the probability can only be determined by choosing a 1 or a 17; you can’t randomly chose a 1 and 17 at the same time. So, the formula is:

P(A or B) = P(A) + P(B)

All this is saying is that given two possible outcomes, the probability occurs independent of each event; they don’t occur at the same time.

P(1 or 17) = P(1)/18 + P(1)/18

P(1 or 17) = 2/18

Since 17 is prime, it’s two and only factors are 1 and 17. The probability of randomly choosing a 1 or 17 is 2/18, meaning that there are 2 elements in the set out of a possible 18 elements that can be randomly chosen.

2/18 simplifies to 1/9

So, your answer is 1/9

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