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dlinn [17]
3 years ago
15

Can someone help with this. Heads up it's ratios

Mathematics
1 answer:
ohaa [14]3 years ago
8 0

Answer:

<em>The median side measures 92 yards</em>

Step-by-step explanation:

Let's call x, y, and z the measures of the sides of the triangle.

The ratios between them are:

\displaystyle \frac{x}{y}=\frac{4}{7}

\displaystyle \frac{x}{z}=\frac{4}{2}=2

The first ratio gives the relation:

\displaystyle y=\frac{7x}{4}

The second ratio can be solved for z:

\displaystyle z=\frac{x}{2}

Since the perimeter is 299 yards:

x+y+z=299

Substituting the above relations:

\displaystyle x+\frac{7x}{4}+\frac{x}{2}=299

Multiplying by 4:

4x + 7x+2x=1196

Joining like terms:

13x=1196

Dividing by 13:

x=1196/13

x=92

Now calculate y:

\displaystyle y=\frac{7\cdot 92}{4}

y = 161

\displaystyle z=\frac{92}{2}

z=46

The median side measures 92 yards

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Width = (x - 5)

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Calculate Area

Area = Length * Width

Area = (x + 5) * (x - 5)

Area = x^2 + 5x - 5x - 25

Area = x^2- 25

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Given

Length = (3x + 4)

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Area =Length * Length

Area =(3x + 4) * (3x + 4)

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Area = 3x^2 + 7x - 6

Width = x + 3

Required: Calculate Length

Area = Length * Width

Length = \frac{Area}{Width}

Length = \frac{3x^2 + 7x - 6}{x + 3}

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Length = \frac{3x^2 + 9x -2x - 6}{x + 3}

Length = \frac{3x(x + 3) -2(x + 3)}{x + 3}

Length = \frac{(3x -2) (x + 3)}{x + 3}

Divide by x + 3

Length = (3x -2)

Solving (4):

Distance = (2y^3 - 7y^2 + 5y -1)

Time = 2y - 1

Required: Determine the average speed

This is calculated as:

Speed = \frac{Distance}{Time}

Speed = \frac{2y^3 - 7y^2 + 5y -1}{2y - 1}

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Speed = \frac{\left(2y-1\right)\left(y^2-3y+1\right)}{2y - 1}

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Multiply (m^2 + 2m - 2) by sum of (m + 3) and (2m - 3)

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Sum = m + 3 + 2m - 3

Sum = m +  2m+3 - 3

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Product = (m^2 + 2m - 2)(3m)

Product = 3m^3 + 6m^2 - 6m

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