Answer:The first, fourth , and last
Step-by-step explanation:
It is correct I took it
Answer:
Therefore, height of the wall at which the ladder is placed is AB = 39.12 foot.
Step-by-step explanation:
Let,
AB = height of the wall at which the ladder is placed
AC = height of the ladder = 40 foot
BC = distance from the wall to the base of the ladder = 8 feet
To Find:
AB = height of the wall at which the ladder is placed = ?
Solution:
Consider a right angled triangle Δ ABC right angle at angle B,
So by Pythagoras theorem we have
AC² = AB² + BC²
Substituting the given values in above equation we get
40² = AB² + 8²
∴ AB² = 40² - 8²
∴ AB² = 1536
Therefore, height of the wall at which the ladder is placed is AB = 39.12 foot.
Cube surface area = side^2 * 6
54 / 6 = side^2
side = sq root (9)
side = 3 centimeters
There is 2000 pounds in 1 ton
Divide 4000 lbs with 2000 lbs
4000/2000 = 2
2 tons is your answer
hope this helps
Answer:
-6x squared + 4x
Step-by-step explanation: