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2 years ago

Which point best approximates V3?

Mathematics

1 answer:

rewona [7]2 years ago

8 0

Answer:

Step-by-step explanation:

because the square root of 3 is 1.7 and B is the closest to that.

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Write a polynomial equation that is best represented by the graph.

Agata [3.3K]

So we gots apolynomial equation that is 3rd degree and crosses x axis at x=-1, x=0 and x=2

the factors of a poly equation that passes through r1,r2,r3 is
(x-r1)(x-r2)(x-r3)

so
r1=-1
r2=0
r3=2
f(x)=(x-(-1))(x-0)(x-2)
f(x)=(x+1)(x)(x-2)
f(x)=x³-x²-2x
leading coefient is posiitve because 3rd degree equations that are postive go bottom left to top right
yah
actually that looks like the exact graph

both
f(x)=(x+1)(x)(x-2)
and
f(x)=x³-x²-2x
are correct

3 0

3 years ago

If f(x) = <img src="https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B9%7D" id="TexFormula1" title="\frac{1}{9}" alt="\frac{1}{9}" align=

boyakko [2]

Answer:

Solution given:

f(x) = $\frac{1}{9}$ x-2

let f(x)=y

y = $\frac{1}{9}$ x-2

interchanging role of x and y

x= $\frac{1}{9}$ y-2

x+2= $\frac{1}{9}$ y

y=9(x+2)

y=9x+18

F-¹(x)=9x+18

and

F-¹(-1)=9*-1+18=-9+18=9

6 0

2 years ago

EASY MATH QUESTION NEED HELP

masha68 [24]

Answer:

6 i think

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

The magnitude and direction of two vectors are shown in the diagram. What is the magnitude of their sum?

VLD [36.1K]

Separate the vectors into their x- and y-components. Let u be the vector on the right and v the vector on the left, so that

u = 4 cos(45°) x + 4 sin(45°) y

v = 2 cos(135°) x + 2 sin(135°) y

where x and y denote the unit vectors in the x and y directions.

Then the sum is

u + v = (4 cos(45°) + 2 cos(135°)) x + (4 sin(45°) + 2 sin(135°)) y

and its magnitude is

||u + v|| = √((4 cos(45°) + 2 cos(135°))² + (4 sin(45°) + 2 sin(135°))²)

… = √(16 cos²(45°) + 16 cos(45°) cos(135°) + 4 cos²(135°) + 16 sin²(45°) + 16 sin(45°) sin(135°) + 4 sin²(135°))

… = √(16 (cos²(45°) + sin²(45°)) + 16 (cos(45°) cos(135°) + sin(45°) sin(135°)) + 4 (cos²(135°) + sin²(135°)))

… = √(16 + 16 cos(135° - 45°) + 4)

… = √(20 + 16 cos(90°))

… = √20 = 2√5

5 0

3 years ago

Read 2 more answers

Graph the linear equation y= -3x using the slope and y intercept 7th grade middle school math pls answer fast this is due soon

ehidna [41]

Answer: graph -3 on the y axis which is the line going straight up and down and then go up one, and then to the right one and graph that point. keep on going up one and to the right one.

Step-by-step explanation:

3 0

3 years ago