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2 years ago

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On a graph the y axis goes by 200’s while the x axis goes by 10’s, I’m given the first equation y=8x+400 and told the slope is 8

which is the same as 200/25, how is that so?

1 answer:

svp [43]2 years ago

3 0

Don’t trust those links it doesn’t work at all

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Line segment XY is tangent to circle Z at point U. Circle Z is shown. Line segment U V is a secant. Line segment X Y is a tangen

Yuri [45]

Answer:

138°

Step-by-step explanation:

∠YUV creates arc YV. Circle Z is made up of arc UV (84°) and arc YV. Solve for the measure of arc YV. (A circle equals 360°)

84° + x = 360°

arc YV = 276°

arc YV is formed from a secant and a tangent. Because of this ∠YUV is half of arc YV.

276° ÷ 2 = 138°

∠YUV = 138°

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2 years ago

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Can someone help me with this question please!!!!!

lianna [129]

Answer:

a = 29

u = 12

Step-by-step explanation:

32 + 7u + 9 + 2a - 3 = 3a + 7u + 9

32 + 2a - 3 = 3a

a = 29

3(29) + 7u + 9 = 180

7u = 180 - 96

7u = 84

u = 12

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2 years ago

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A survey revealed that 56% of the students at North Valley high school are involved with in a sports team. The survey also showe

oksano4ka [1.4K]

Answer:

The probability that a student who is involved in a sports team also participated in the prom dance = 0.1344

Step-by-step explanation:

56% of the students are involved in a sport team

56% = 0.56

According to the question, it is stated that 24% of the students at the school that are involved in a sports team also participated in the prom dance.

24% = 0.24

This means that we are going to find 24% of the original 56%, since 24% of them also participated in the prom dance.

The probability that a student who is involved in a sports team also participated in the prom dance = 0.24 * 0.56

The probability that a student who is involved in a sports team also participated in the prom dance = 0.1344

5 0

2 years ago

Jasmine needs to reduce the height of a picture from five inches to two inches so it will fit in the yearbook. What percentage o

sasho [114]

<em>The picture's height was reduced by </em><em><u>60% to 40%</u></em>

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3 years ago

Consider the sequence defined recursively by do = 0, an = an-1 + 3n – 1. a) Write out the first 5 terms of this sequence,

creativ13 [48]

Answer:

The first 5 terms of the sequence is 2,7,15,26,40.

Step-by-step explanation:

Given : Consider the sequence defined recursively by $a_0=0$ $a_n=a_{n-1}+3n-1$

To find : Write out the first 5 terms of this sequence ?

Solution :

$a_n=a_{n-1}+3n-1$ and $a_0=0$

The first five terms in the sequence is at n=1,2,3,4,5

For n=1,

$a_1=a_{1-1}+3(1)-1$

$a_1=a_{0}+3-1$

$a_1=0+2$

$a_1=2$

For n=2,

$a_2=a_{2-1}+3(2)-1$

$a_2=a_{1}+6-1$

$a_2=2+5$

$a_2=7$

For n=3,

$a_3=a_{3-1}+3(3)-1$

$a_3=a_{2}+9-1$

$a_3=7+8$

$a_3=15$

For n=4,

$a_4=a_{4-1}+3(4)-1$

$a_4=a_{3}+12-1$

$a_4=15+11$

$a_4=26$

For n=5,

$a_5=a_{5-1}+3(5)-1$

$a_5=a_{4}+15-1$

$a_5=26+14$

$a_5=40$

The first 5 terms of the sequence is 2,7,15,26,40.

5 0

2 years ago