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3 years ago

6

On a graph the y axis goes by 200’s while the x axis goes by 10’s, I’m given the first equation y=8x+400 and told the slope is 8

which is the same as 200/25, how is that so?

1 answer:

svp [43]3 years ago

3 0

Don’t trust those links it doesn’t work at all

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3 years ago

Can someone help me understand how to do this?

Crazy boy [7]

Answer:

1/3

Step-by-step explanation:

To get no solution, you want to get rid of x and leave an incorrect equation.

In this case, we will use 1/3x.

1/3x + 2 = 1/3x - 3

We subtract 1/3x on both sides. This will cause the 1/3x's to cancel out.

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3 years ago

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Gnesinka [82]

Answer:

89

Step-by-step explanation:

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3 years ago

Simplify: 18q2−45q+25/9q2−25.

Svet_ta [14]

Answer:

$\frac{(6q-5)}{(3q+5)}$

Step-by-step explanation:

Given: $\frac{18q^{2}-45q+25 }{9q^{2}-25 }$

Factorizing the numerator and the denominator, we have:

18 $q^{2}$ - 45q + 25 = 18 $q^{2}$ - 30q - 15q + 25

= (3q - 5)(6q - 5)

and

9 $q^{2}$ - 25 = (3q - 5)(3q + 5)

So that,

$\frac{18q^{2}-45q+25 }{9q^{2}-25 }$ = $\frac{(3q-5)(6q-5)}{(3q-5)(3q+5)}$

= $\frac{(6q-5)}{(3q+5)}$

Therefore,

$\frac{18q^{2}-45q+25 }{9q^{2}-25 }$ = $\frac{(6q-5)}{(3q+5)}$

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3 years ago