Ask question

Ask question

All categories

svetoff [14.1K]

3 years ago

10

The area of a square mirror is 256 squared inches. A rectangle mirror has a width the same as the square mirror's width. It's Le

ngth is two inches longer than its width. What is the area of the rectangular mirror?

1 answer:

Ludmilka [50]3 years ago

4 0

The formula of the area of a square is the side length squared. So to get the width of the rectangle, you need to square root the area of the square. The square root of 256 is 16, therefore the width of the rectangle is also 16 inches. Since the length of the rectangle is 2 inches longer, you add 2 to 16, which gives you 18 inches.

The formula for the area of a rectangle is the length multiplied by the width.

18*16=288. The area of the rectangle is 288 inches.

You might be interested in

Find the perimeter of a triangle with vertices A(2,5) B(2,-2) C(5,-2). Round your answer to the nearest tenth and show your work

valina [46]

Answer:

Step-by-step explanation:

Question

Find the perimeter of a triangle with vertices A(2,5) B(2,-2) C(5,-2). Round your answer to the nearest tenth and show your work.

perimeter of a triangle = AB+AC+BC

Using the distance formula

AB = sqrt(-2-5)²+(2-2)²

AB = sqrt(-7)²

AB =sqrt(49)

AB =7

BC = sqrt(-2+2)²+(2-5)²

BC = sqrt(0+3²)

BC =sqrt(9)

BC =3

AC= sqrt(-2-5)²+(2-5)²

AC= sqrt(-7)²+3²

AC =sqrt(49+9)

AC =sqrt58

Perimeter = 10+sqrt58

5 0

2 years ago

46 Two light houses ash their lights every 30 seconds and 40 seconds respectively. Given that they last ashed together at 10:40

IRISSAK [1]

30,60,90,120
40,80,120

they will both " ash " in 120 seconds (thats 2 minutes)...so they will both ash at
10:42 a.m.

8 0

3 years ago

Solve these simultaneous equations 2x+3y=13 4x-y=-2

Neko [114]

X = 1/2 y = 4 by elimination

6 0

3 years ago

Read 2 more answers

A builder wants to build the bridge whose cross section is shown in the diagram. Two companies offer simple bids on building the

leva [86]

The length of the bridge is the distance from the beginning to the end.

<em>The distance b between each beam is 9ft.</em>

Let:

<em /> $I \to$ <em> I-Beam</em>

<em /> $d_I \to$ <em> distance between I beam and the bridge</em>

<em /> $b \to$ <em> distance between each I beam</em>

<em />

Given that:

$I = \frac 34 ft\\$

$d_I = 3 ft$

<em /> $Length = 55ft\ 6in$ <em> --- length of the bridge</em>

<em />

From the diagram (see attachment), there are: 6 I-beams.

So, the length of the 6 I-beams is:

$L_1 = 6 \times I$

$L_1 = 6 \times \frac 34$

$L_1 = \frac {18}4$

$L_1 = 4.5ft$

There are 2 I-beams beside the bridge

So, the distance between the 2 I-beams and the bridge is:

$d_1 =2 \times d_I$

$d_1 =2 \times 3ft$

$d_1 =6ft$

There are 5 spaces between the I-beams

So, the length of the total spaces is:

$L_2 = 5 \times b$

$L_2 = 5b$

The total length is:

$Length = L_1 + d_1 + L_2$

So, we have:

$4.5ft + 6ft + 5b = 55ft\ 6in$

Collect like terms

$5b = 55ft\ 6in - 4.5ft - 6ft$

$5b = 44.5ft\ 6in$

Convert inches to feet

$5b = 44.5ft\ + \frac{6}{12}ft$

$5b = 44.5ft\ + 0.5ft$

$5b = 45ft$

Divide both sides by 5

$b = 9ft$

<em>Hence, the distance (b) between each beam is 9ft.</em>

Read more about lengths at:

brainly.com/question/22059747

3 0

2 years ago

in an 7th grade class with 80 people, seven tenths of the students wore shorts, if three sevenths of those students who wore sho

Trava [24]

Answer:

56

Step-by-step explanation:

8 0

2 years ago

Read 2 more answers