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2 years ago

Ill mark brainilist or whatever, just answer please fast. Need this done asap

Mathematics

2 answers:

mylen [45]2 years ago

7 0

True.

plug in and the statement is true

Archy [21]2 years ago

6 0

Answer:

true

Step-by-step explanation:

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2. A physical fitness researcher devises a test of strength and finds that the results are normally distributed with a mean of 1

julia-pushkina [17]

Answer:

Step-by-step explanation:

A physical fitness researcher devises a test of strength and finds that the results are normally distributed with a mean of 110 pounds and a standard deviation of 10.4 pounds. If a subject is randomly selected and measured, find the probability of a score between 110 and 128 pounds. (5

7 0

2 years ago

What is the answer to graphing this equation y= -4x

MAXImum [283]

Answer:

x=0

Step-by-step explanation:

7 0

2 years ago

Tony had a certain number of stamps that were each worth $0.15. he misplaced 7 stamps. he found that the total value of his stam

patriot [66]

( 5.55 / .15 ) + 7 x .15 = s

6 0

3 years ago

A perfect square is the square of an integer. Of the integers from 2 through 99, how many have at least one perfect square facto

N76 [4]

Answer:

Six numbers have perfect square factors

Step-by-step explanation:

The numbers with perfect square factors are those numbers that have perfect squares as one of the numbers that can divide them.

They include:

4 = 2 * 2

16 = 4 * 4

36 = 6 * 6

49 = 7 * 7

64 = 8 * 8

81 = 9* 9

These numbers above have perfect square factors because they are formed from integers that multiply themselves.

8 0

2 years ago

Consider three boxes with numbered balls in them. Box A con- tains six balls numbered 1, . . . , 6. Box B contains twelve balls

murzikaleks [220]

Answer:

a) 0.73684

b) 2/3

Step-by-step explanation:

part a)

$P ( A is 1 / exactly two balls are 1) = \frac{P ( A is 1 and that exactly two balls are 1)}{P (Exactly two balls are one)}$

Using conditional probability as above:

(A,B,C)

Cases for numerator when:

P( A is 1 and exactly two balls are 1) = P( 1, not 1, 1) + P(1, 1, not 1)

= $(\frac{1}{6}* \frac{11}{12}*\frac{1}{4}) + (\frac{1}{6}*\frac{1}{12}*\frac{3}{4}) = 0.048611111$

Cases for denominator when:

P( Exactly two balls are 1) = P( 1, not 1, 1) + P(1, 1, not 1) + P(not 1, 1 , 1)

$= (\frac{1}{6}* \frac{11}{12}*\frac{1}{4}) + (\frac{1}{6}*\frac{1}{12}*\frac{3}{4}) + (\frac{5}{6}*\frac{1}{12}*\frac{1}{4})= 0.0659722222$

Hence,

$P ( A is 1 / exactly two balls are 1) = \frac{P ( A is 1 and that exactly two balls are 1)}{P (Exactly two balls are one)} = \frac{0.048611111}{0.06597222} \\\\= 0.73684$