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2 years ago

Write an algebraic expression for the word expression. Use n for the

Mathematics

1 answer:

KonstantinChe [14]2 years ago

6 0

Answer:

11+n

Step-by-step explanation:

eleven increased by a number

11+n

hope it helps

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Solve step by step solution then only i can do it plxx

Anuta_ua [19.1K]

Answer:

<h3><u>Let's</u><u> </u><u>understand the concept</u><u>:</u><u>-</u></h3>

Here angle B is 90°

So $\triangle ABC$ and $\triangle ABD$ Are right angled triangle

So we use Pythagoras thereon for solution

<h3><u>Required Answer</u><u>:</u><u>-</u></h3>

First in triangle ABC

perpendicular=p=8cm

Hypontenuse =h =10cm

We need to find base=b

According to Pythagoras thereon

${\boxed{\sf b^2=h^2-p^2}}$

Substitutethe values

$\longrightarrow$ $\sf b^2=10^2-p^2$

$\longrightarrow$ $\sf b={\sqrt {10^2-8^2}}$

$\longrightarrow$ $\sf b={\sqrt{100-64}}$

$\longrightarrow$ $\bf b={\sqrt {36}}$

$\longrightarrow$ $\sf b=6$

$\therefore$ $\overline{BC}=6cm$

BD=BC+CD

$\longrightarrow$ $BD=9+6$

$\longrightarrow$ $BD=15cm$

Now in $\triangle ABD$

Perpendicular=p=8cm

Base =b=15cm

We need to find Hypontenuse =AD(x)

According to Pythagoras thereon

${\boxed {\sf h^2=p^2+b^2}}$

Substitute the values

$\longrightarrow$ $\sf h^2=8^2+15^2$

$\longrightarrow$ $\sf h={\sqrt {8^2+15^2}}$

$\longrightarrow$ $\sf h={\sqrt {64+225}}$

$\longrightarrow$ $\sf h={\sqrt {289}}$

$\longrightarrow$ $\sf h=17cm$

$\therefore$ ${\underline{\boxed{\bf x=17cm}}}$

3 0

2 years ago

6th term in numerical pattern that begins with 2 and then adds 5

inysia [295]

Answer:

Step-by-step explanation:

2, 7, 12, 17, 22, 27

7 0

2 years ago

Witch operation should you do first when you simplify 85+ (25 x 5)?

olya-2409 [2.1K]

Answer:

25X5

Step-by-step explanation:

If you follow the PEMDAS rule the first thing you must do is the equation inside the parenthesis.

Parenthesis

Exponents

Multiplication

Division

Addition

Subtraction

7 0

2 years ago

Read 2 more answers

Pls help pls help pls help

aliya0001 [1]

Sin C= 3/5
Your answer would be A

7 0

2 years ago

The perimeter of a pool is 96 feet. If the length of the pool is 3 times its width, what is the width of the pool? Labeling the

k0ka [10]

Answer:

12 feets

Step-by-step explanation:

Let the area of the pool be Length×width

There will be 2lengths and 2widths as well so the perimeter of the pool will be the addition of all the sides of the pool i.e 2L + 2W = 96... (1)

And since the length of the pool is 3 times its width, we have

L = 3W... (2)

Substituting equation 2 into 1 to get the width 'W'

2(3W) + 2W = 96

6W + 2W = 96

8W = 96

W = 96/8

W = 12feets

The width of the pool is 12feets

4 0

3 years ago