Step-by-step explanation:
this is the answer
This is really confusing to me
2 answers:
One of the properties of parallelograms is that the diagonals must bisect each other, that means that each diagonal is divided into two equal parts by the point at which they cross (see picture).
Your diagonals are AC and BD, and they cross at point E. That means BE = DE (which you are told) and AE = EC for it to be a parallelogram. You're given that AE = 6x - 15 and EC = x + 30. Because they must be equal to create a parallelogram, set those values equal to each other and solve for x:
x must equal 9 for ABCD to be a parallelogram.
Your diagonals are AC and BD, and they cross at point E. That means BE = DE (which you are told) and AE = EC for it to be a parallelogram. You're given that AE = 6x - 15 and EC = x + 30. Because they must be equal to create a parallelogram, set those values equal to each other and solve for x:
x must equal 9 for ABCD to be a parallelogram.
You might be interested in
Answer:
a)19.28≈x (rounded to the nearest hundredth)
b)7.66≈x (rounded to the nearest hundredth)
c)x≈8.39(rounded to the nearest hundredth)
d)x≈36.87 (rounded to the nearest hundredth) and y=5
Step-by-step explanation:
I'm going to first assume that all of these are right triangles.
If you look at the hint, it says SOHCAHTOA
This stands for the trigonometric functions
SOH tells us that sine(θ)=opposite/hypotenuse
CAH tells us that cosine(θ)=adjacent/hypotenuse
TOA tells us that tangent(θ)=opposite/adjacent
(ps. θ, or theta, stands for any angle measure)
Now, let's look at problem a.
We have the value of the hypotenuse and the value of an angle. We want to find the side opposite from the angle. So, in this case, we want to use the sine function.
sin(40)=x/30
30*sin(40)=x
19.28≈x (rounded to the nearest hundredth)
We can solve the other problems in a similar fashion.
Problem b
We have the hypotenuse, an angle measure, and we want to find the adjacent side. This is telling us to use the cosine function.
cos(40)=x/10
10*cos(40)=x
7.66≈x (rounded to the nearest hundredth)
Problem c
We have an angle measure, an adjacent value, and we want to find the opposite length, so we're going to use the tangent function.
tan(40)=x/10
10*tan(40)=x
x≈8.39(rounded to the nearest hundredth)
Problem d
We need to first solve for x, the angle measure.
We have an opposite length, an adjacent length, so we can use the tangent function to solve for the missing angle
Let's set up an equation
tan(x)=3/4
Using or tangent inverse to cancel out the tangent, we get
x=(3/4)
x≈36.87 (rounded to the nearest hundredth)
Now, let's solve for y, the hypotenuse!
Both the sine and cosine functions work, so I'm just going to pick one.
sine(36.87)=3/y
y*sin(36.87)=3
y=3/sin(36.87)
y=5
Side note: Although I rounded the angle measure, when calculating the y value, on my calculator, I did not round the value. Don't round until the end on your calculator, but it's okay to round on your paper.
PS. I used degrees for the angle measures, not radians, so if you want to retry these problems, make sure your calculator is calculating degrees, not radians, or else you might get some funky answers.