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GaryK [48]
3 years ago
10

A magnetic field (B=3.2x10^-3 T) passes perpendicular through a circular loop of wire ( radius= 5.0 cm) what is the magnetic flu

x through the hoop?
Physics
1 answer:
weqwewe [10]3 years ago
8 0

Answer:

25.12 x 10^-6 T/m^2

Explanation:

Magnetic flux is

fi = B * A * cos theta

as filed passes perepndicular theta is 90degrees and cos theta is 1

B=3.2x10^-3 T

A = pi * r ^2

A = 3.14 * (0,05m )^2

A = 0,00785

A = 7,85 m 10^-3 m2

fi = 3.2x10^-3 T * 7,85 m 10^-3 m2

fi = 25.12 x 10^-6 T/m^2

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The net force acting on an object equals the applied force plus the force of friction.
Georgia [21]

Answer:

False

Explanation:

The net force is equal to the applied force minus the force of friction. It is possible for friction to act in the same direction as an applied force, but that would mean there would have to be more than two forces acting on the object.

3 0
3 years ago
A proton is released from rest at the positive plate of a parallelplatecapacitor. It crosses the capacitor and reaches the negat
Triss [41]

Answer:

2.1406 ×10^6 m/sec

Explanation:

we know that energy is always conserved

so from the law of energy conservation

qV=\frac{1}{2}mv^2

here V is the potential difference  

we know that mass of proton = 1.67×10^{-27} kg

we have given speed =50000m/sec

so potential difference V=\frac{\frac{1}{2}\times 1.67\times 10^{-27}50000^2}{1.6\times 10^{-19}}=13.045

now mass of electron =9.11×10^{-31}

so for electron

\frac{1}{2}\times 9.11\times 10^{-31}v^2=1.6\times 10^{-19}\times 13.045=2.1406\times 10^6 m/sec

so the velocity of electron will be 2.1406×10^6 m/sec

4 0
4 years ago
Explain why an experiment should test only one variable at a time
padilas [110]
We use only one variable at a time to find the accurate result. We want to see how the result of experiment changes everytime with a single variable.
4 0
3 years ago
Find the first three harmonics of a string of linear mass density 2.00 g/m and length 0.600 m when the tension in it is 50.0 n.
blsea [12.9K]

As we know that Nth harmonic of the string is given by

f = \frac{N}{2L}\sqrt{\frac{T}{m/L}}

now here we will have

m/L = mass density = 2 g/m

m/L = 0.002 kg/m

Length = L = 0.600 m

Tension = T = 50.0 N

now from above formula we have

f = \frac{N}{2(0.600)}\sqrt{\frac{50.0}{0.002}}

f = 131.8N

now for first harmonic N = 1

f_1 = 131.8 Hz

for second harmonic N = 2

f_2 = 263.5 Hz

for third harmonic N = 3

f_3 = 395.3 Hz

8 0
4 years ago
GIVING BRAINLY AND THIS IS A BASKETBALL QUESTION
luda_lava [24]

Answer:

Jump Ball; used to start the game. The referee throws the ball up in the air, above two members of opposite teams, who have to jump up to try and tap the ball towards one of their teammates.

Assist: a pass made from one player to another, that directly leads to making a basket. For a pass to count as an assist, the ball has to be passed directly to the played who scores, and points must be earned.

Steal: when a defensive player intercepts the ball from an offensive player.

Lay Up: a shot made from below, by running up to the basket from the side, jumping, and bouncing the ball off of the backboard, into the basket.

Technical Foul: a foul given for "unsportsmanlike behaviour", such as making fun of an opponent.

5 0
3 years ago
Read 2 more answers
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