<span>0.506 m/s^2
Given the arrangement of rope and the man, he's effectively suspended by a rope from a frictionless pulley. So he's pulling the rope with a force of 371 n causing him to be pulled upwards by his arms. Additionally, the rope goes up to the pulley and back down to the man causing an additional 371 n of force pulling him upwards. So the total force being used to lift the man is 742 n.
Additionally, the man is being pulled downwards by gravity at 9.80 m/s^2. And since he masses 72.0 kg, the downward force in newtons is 72.0 kg * 9.80 m/s^2 = 705.6 n downward.
So the total force being exerted on the man is
742 n - 705.6 n = 36.4 n
To calculate his acceleration, simply divide the number of newtons applied by his mass.
36.4 kg m/s^2 / 72.0 kg = 0.505556 m/s^2
And round to 3 significant figures.
0.505556 m/s^2 = 0.506 m/s^2</span>
Just a guess without asking Google, that without the sun's gravity holding us in orbit, we would end up drifting whatever direction we were headed as it disappeared?
Answer:
t = 3.35 s
Explanation:
It is given that,
Mass of a pumpkin, m = 8 kg
It is dropped from a height of 55 m
We need to find the time taken by it to hit the ground.
Initial velocity of the pumpkin, u = 0
Using second equation of motion to find it as follows :
So, it will take 3.35 seconds to hit the ground.
The final velocity of the 14 kg object is 1.6 m/s in the same direction
Explanation:
We can solve this problem by using the law of conservation of momentum: the total momentum of the system must be conserved before and after the collision. Therefore, we can write
where:
is the mass of the first object
is the initial velocity of the first object
is the final velocity of the first object
is the mass of the second object
is the initial velocity of the second object
is the final velocity of the second object
Re-arranging the equation and substituting the values, we find:
And the direction is the same as the initial direction, since it has the same sign.
Learn more about conservation of momentum:
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