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goldfiish [28.3K]
3 years ago
7

A seafood restaurant claims an increase of $1,750.00 over its average profit during a week where it introduced a special of bake

d clams
A.if this is true,how much extra profit did it revive per day.

B.if it had,instead,lost $150 per day how much money would it have lost for the week.

C.if its total loss was $490 for the week, what was its average daily change.

Please help me!!
Mathematics
1 answer:
kolezko [41]3 years ago
8 0
I belive B. is 700$, for the rest i dont know
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How to set the answer up
Korolek [52]

Let s and g represents the numbers of suits and gowns produced.

The number of zippers used is 2s+g.

The number of buttons used is 5s+8g.

In order to use all of the available zippers and buttons, we must have ...

  • 2s + g = 171
  • 5s + 8g = 576

Cramer's rule tells you the solution to the system

  • ax +by = c
  • dx +ey = f

Is given by

  • x = (bf-ey)/(bd-ea)
  • y = (cd-fa)/(bd-ea)

Using this rule on the equations for zippers and buttons, we have

... s = (1·576 -8·171)/(1·5 -8·2) = -792/-11 = 72

... g = (171·5 -2·576)/-11 = -297/-11 = 27

72 suits and 27 gowns can be made from available zippers and buttons.

3 0
3 years ago
Which pairs of angles are alternate exterior angles? select yes or no​
sasho [114]

A - No

B - No

C - Yes

D - Yes

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C and D are alternate exterior angles

8 0
3 years ago
Y=4x the y intercept of ?
PSYCHO15rus [73]
The y intercept of that rule is 0
7 0
3 years ago
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A bag contains 4 red balls, 2 green balls, 3 yellow balls, and 5 blue balls. Find each probability for randomly removing balls w
AfilCa [17]

Answer:

\frac{15}{4802}, \frac{15}{9604}, \frac{9}{2401}, \frac{9}{4802}

Step-by-step explanation:

The bag has a total of (4+2+3+5) = 14 balls. Set up the proportions:

Red: \frac{4}{14}

green: \frac{2}{14}

yellow: \frac{3}{14}

blue: \frac{5}{14}

Now solve!

Removing 1 yellow, 1 red, 1 green, and 1 blue = \frac{3}{14} \cdot \frac{4}{14}  \cdot \frac{2}{14}  \cdot \frac{5}{14} =\frac{15}{4802}

Removing 1 blue, 1 green, 1 green, and 1 yellow = \frac{5}{14} \cdot \frac{2}{14}  \cdot \frac{2}{14}  \cdot \frac{3}{14} =\frac{15}{9604}

Removing 1 red, 1 red, 1 yellow, and 1 yellow = \frac{4}{14} \cdot \frac{4}{14}  \cdot \frac{3}{14}  \cdot \frac{3}{14} =\frac{9}{2401}

Removing 1 green, 1 yellow, 1 yellow, and 1 red = \frac{2}{14} \cdot \frac{3}{14}  \cdot \frac{3}{14}  \cdot \frac{4}{14} =\frac{9}{4802}

4 0
2 years ago
Figure TUVW ≅ figure ABCD, AB = 12, CD = 6, and DA = 4.
Olegator [25]
The measure of VW is 6. It's because since the figures are congruent their names are written in correspondence ....so since VW corresponds to CD , the answer must be 6.
6 0
3 years ago
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