Answer:
3.74
Step-by-step explanation:
Use Pythagorean theorem
2.5^2=x^2=4.5^2
x=3.74
-np-4≤2(c-3)
-np-4≤2x-6
-np≤2x-2
-n≤(2x-2)/p
n≥-((2x-2)/p)
Let the temperature at 10am be x, then
x + 8 = 56
x = 56 - 8 = 48 degrees F
Let y be the temperature at 8am, then
y - 2 = 48
y = 48 + 2 = 50 degrees.
Split up the integration interval into 4 subintervals:
![\left[0,\dfrac\pi8\right],\left[\dfrac\pi8,\dfrac\pi4\right],\left[\dfrac\pi4,\dfrac{3\pi}8\right],\left[\dfrac{3\pi}8,\dfrac\pi2\right]](https://tex.z-dn.net/?f=%5Cleft%5B0%2C%5Cdfrac%5Cpi8%5Cright%5D%2C%5Cleft%5B%5Cdfrac%5Cpi8%2C%5Cdfrac%5Cpi4%5Cright%5D%2C%5Cleft%5B%5Cdfrac%5Cpi4%2C%5Cdfrac%7B3%5Cpi%7D8%5Cright%5D%2C%5Cleft%5B%5Cdfrac%7B3%5Cpi%7D8%2C%5Cdfrac%5Cpi2%5Cright%5D)
The left and right endpoints of the 
-th subinterval, respectively, are
for 
, and the respective midpoints are
We approximate the (signed) area under the curve over each subinterval by
so that
We approximate the area for each subinterval by
so that
We first interpolate the integrand over each subinterval by a quadratic polynomial 
, where
so that
It so happens that the integral of reduces nicely to the form you're probably more familiar with,
Then the integral is approximately
Compare these to the actual value of the integral, 3. I've included plots of the approximations below.
The volume of cube and rectangular prism are same. Option B.
Step-by-step explanation:
Given,
The length of the edge of the cube (a) = 5 cm
The dimension of rectangular prism (l×b×h) = 5 cm×25 cm×1 cm
To find the relation between the volume of cube and rectangular prism.
Formula
The volume of a cube = a³ cube cm
The volume of rectangular prism = l×b×h cube cm
Now,
The volume of a cube = 5³ cube cm = 125 cube cm
The volume of rectangular prism = 5×25×1 cube cm = 125 cube cm
Hence,
The volume of cube and rectangular prism are same.
