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murzikaleks [220]
3 years ago
6

Help me ASAP plsssssssssssssssssssssssssssssssssss

Mathematics
1 answer:
SCORPION-xisa [38]3 years ago
4 0
The answer is 7 because it goes 10th 100th and the thirty one is thousands
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Karen Sullivan delivers newspapers for the Tribune dispatch. She receives 18.2 cents per paper, six days a week (for the daily p
mario62 [17]

Answer:

About $241.11

Step-by-step explanation:

So, Karen receives 18.2 cents per paper.

She delivers 124 paper per day.

In other words, on days other than Sunday, she will make a total of:

18.2(124)=2256.8\text{ cents}

On Sunday, each paper is sold for $0.70 or 70 cents. She also sells 151 Sunday papers. Thus, on a Sunday, she will make a total of:

70(151)=10570\text{ cents}

Therefore, in one week, she will do the first equation six times and the Sunday equation once. Thus, her total pay will be:

6(2256.8)+10570=24110.8\text{ cents}\approx\$241.11

4 0
3 years ago
You are having a pizza-making party. You will need 6 ounces of dough and 4 ounces of sauce for each person at the party (includi
Len [333]

Answer:

Gyeyuegtee2ugt2egt2fekufwetuifkueyr2v4xtk63ur Gyeyuegtee27gt2egt2fwk7fwet7ifkue6r2v4ftk63 trviugrxrt6uk3 gtyr7ix txyt 4t ulu66tt xflut I r t4e1ttrxl86vt4tt6tr63t3r6te3y2tyewdgydgey3dgyywgewsyfwdgy

7 0
3 years ago
If she spent a total of $44.25 on fabric, what was the cost per yard? She bought 14 3/4. Explain how you solved
Deffense [45]

44.25 \div 14.75 = 3
$44.25 total divided by how many yards (14.75) = $3/yard
6 0
3 years ago
Select all the correct answers.
irina1246 [14]

Operations that can be applied to a matrix in the process of Gauss Jordan elimination are :

replacing the row with twice that row

replacing a row with the sum of that row and another row

swapping rows

Step-by-step explanation:

Gauss-Jordan Elimination is a matrix based way used to solve linear equations or to find inverse of a matrix.

The elimentary row(or column) operations that can be used are:

1. Swap any two rows(or colums)

2. Add or subtract scalar multiple of one row(column) to another row(column)

as is done in replacing a row with sum of that row and another row.

3. Multiply any row (or column) entirely by a non zero scalar as is done in replacing the row with twice the row, here scalar used = 2

6 0
3 years ago
-x + 6y = -8 <br> x-6y=8
PilotLPTM [1.2K]

Answer:

inifinitely many solutions

Step-by-step explanation:

3 0
3 years ago
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