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3 years ago

8x - 9 - 5x = 3x - 36 - 18x

Mathematics

1 answer:

makkiz [27]3 years ago

8 0

Answer:

$8x - 9 - 5x = 3x - 36 - 18x \\ 8x - 5x - 9 = 3x - 18x - 36 \\ 3x - 9 = - 15x - 36 \\ 3x = - 15x - 36 + 9 \\ 3x = - 15x - 27 \\ 3x + - 15x = - 27 \\ - 12x = - 27 \\ x = \frac{ 27}{12}$

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yall know what im not posting anything else i was going to post a 400 point question but all yall doing is commenting for points

astra-53 [7]

Answer:

SO is this a question????????????????/

Step-by-step explanation:

This is kinda confusing :/

8 0

3 years ago

Read 2 more answers

Assume that women's heights are normally distributed with a mean given by mu equals 62.5 in,and a standard deviation given by

Misha Larkins [42]

Answer:

(a) 0.5899

(b) 0.9166

Step-by-step explanation:

Let X be the random variable that represents the height of a woman. Then, X is normally distributed with

$\mu$ = 62.5 in

$\sigma$ = 2.2 in

the normal probability density function is given by

$f(x) = \frac{1}{\sqrt{2\pi}2.2}\exp{-\frac{(x-62.5)^{2}}{2(2.2)^{2}}}$ , then

(a) $P(X < 63) = \int\limits_{-\infty}^{63}f(x) dx$ = 0.5899

(in the R statistical programming language) pnorm(63, mean = 62.5, sd = 2.2)

(b) We are seeking $P(\bar{X} < 63)$ where n = 37. $\bar{X}$ is normally distributed with mean 62.5 in and standard deviation $2.2/\sqrt{37}$ . So, the probability density function is given by

$g(x) = \frac{1}{\sqrt{2\pi}\frac{2.2}{\sqrt{37}}}\exp{-\frac{(x-62.5)^{2}}{2(2.2/\sqrt{37})^{2}}}$ , and

$P(\bar{X} < 63) = \int\limits_{-\infty}^{63}g(x)dx$ = 0.9166

(in the R statistical programming language) pnorm(63, mean = 62.5, sd = 2.2/sqrt(37))

You can use a table from a book to find the probabilities or a programming language like the R statistical programming language.

4 0

3 years ago

a manufacturer is designing a flashlight for the flashlight to admit a focused beam the bull needs to be on the central axis of

Helen [10]

Answer:

y= 1/12(x-0)^2+0

this answer works as an upward parabola

Step-by-step explanation:

The formula for a veritcal parabola is y=1/4p(x-h)^2+k
(h,k)= coordinates of the vertex of the parabola
p= absolute value of the distance from the vertex to the focus/directrix
In this problem, it is given that the vertex is at the origin (0,0) and the focus (the bulb), is 3 centimeters away from the vertex.
Now, you know the values of the variables. Fill in the values
FROM THE FORMULA: 1/4p turns into 1/12 since p is 3.
(x-h)^2+k turns into (x-0)^2+0, since h and k where the values of the vertex which was 0,0
once all the variables are given values (except x and y) you have made your equation!
The answer is y=1/12(x-0)^2+0

MARK BRAINLIEST! this took forever, and I know this is the right answer since I got a perfect grade when I turned mine in.

8 0

3 years ago

How can you know if statement is true? 1/2+3/8=4/10=2/5

mixas84 [53]

Answer:

Actually that's incorrect

Step-by-step explanation:

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3 years ago

117 X x + 3 Find the value of x. A. 4 В. 5 C. 6 D. 9

Andre45 [30]

Answers:

1. D po

Step-by-step explanation:

i hope its hepl

3 0

3 years ago