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ad-work [718]
3 years ago
10

This is some question pizza circles in math

Mathematics
1 answer:
lina2011 [118]3 years ago
5 0

Step-by-step explanation:

Diameter : 10

Radius : 5

Area :

\pi {r}^{2}  =  \pi{5}^{2}  = 78.54

Diameter: 18

Radius : 9

Area :

\pi {9}^{2}  = 254.47

Diameter: 11

Radius: 5.5

Area:

\pi {5.5}^{2}  = 95.03

Diameter: 12

Radius : 6

Area:

\pi {6}^{2}  = 113.09

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5.26 meters per second

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Evaluate the expression for m=4 n=5 p=-2<br> mn^p
Serga [27]

Answer:

<h2>mn^p = 4×(5^-2)</h2><h2> =4×0.04</h2><h2> =0.16</h2>

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-6n5x^3÷18nx^7<br>12m^8y^6÷-9my^4​
umka2103 [35]

Answer:

(-n^4 - 4 m^7 x^4 y^2)/(3 x^4)

Step-by-step explanation:

Simplify the following:

(-6 n^5 x^3)/(18 n x^7) + (12 m^8 y^6)/(-9 m y^4)

The gcd of -6 and 18 is 6, so (-6 n^5 x^3)/(18 n x^7) = ((6 (-1)) n^5 x^3)/((6×3) n x^7) = 6/6×(-n^5 x^3)/(3 n x^7) = (-n^5 x^3)/(3 n x^7):

(-1 n^5 x^3)/(3 n x^7) + (12 m^8 y^6)/(-9 m y^4)

Combine powers. (-n^5 x^3)/(3 n x^7) = (n^(5 - 1) x^(3 - 7) (-1))/3:

-(n^(5 - 1) x^(3 - 7))/3 + (12 m^8 y^6)/(-9 m y^4)

5 - 1 = 4:

-(n^4 x^(3 - 7))/3 + (12 m^8 y^6)/(-9 m y^4)

3 - 7 = -4:

-(n^4 x^(-4))/3 + (12 m^8 y^6)/(-9 m y^4)

The gcd of 12 and -9 is 3, so (12 m^8 y^6)/(-9 m y^4) = ((3×4) m^8 y^6)/((3 (-3)) m y^4) = 3/3×(4 m^8 y^6)/(-3 m y^4) = (4 m^8 y^6)/(-3 m y^4):

(4 m^8 y^6)/(-3 m y^4) - (n^4)/(3 x^4)

Combine powers. (4 m^8 y^6)/(-3 m y^4) = (4 m^(8 - 1) y^(6 - 4))/(3 (-1)):

-(n^4)/(3 x^4) + (4 m^(8 - 1) y^(6 - 4))/(-3)

8 - 1 = 7:

-(n^4)/(3 x^4) + (4 m^7 y^(6 - 4))/(-3)

6 - 4 = 2:

-(n^4)/(3 x^4) + (4 m^7 y^2)/(-3)

Multiply numerator and denominator of (4 m^7 y^2)/(-3) by -1:

-4/3 m^7 y^2 - (n^4)/(3 x^4)

Put each term in -(n^4)/(x^4×3) - (4 m^7 y^2)/3 over the common denominator 3 x^4: -(n^4)/(x^4×3) - (4 m^7 y^2)/3 = (-n^4)/(3 x^4) - (4 m^7 x^4 y^2)/(3 x^4):

-n^4/(3 x^4) - (4 m^7 x^4 y^2)/(3 x^4)

-n^4/(3 x^4) - (4 m^7 x^4 y^2)/(3 x^4) = (-n^4 - 4 m^7 x^4 y^2)/(3 x^4):

Answer: (-n^4 - 4 m^7 x^4 y^2)/(3 x^4)

5 0
3 years ago
Identify the function family that each belongs to: a. linear b. exponential c. quadratic d. linear absolute value f(x)=x+2 f(x)=
Dmitriy789 [7]

The function family that each belongs to are :

a. linear = f(x)=x+2

b. exponential = f(x)=2^x

c. quadratic = f(x)=x^2

d. linear absolute value = f(x)=|2x|

A linear function should have either one or more variables without exponential form

A quadratic function should have either one or more variables with exponential form with degree 2

An exponential function has a variable raised to the power constant

A linear absolute contains a absolute value expression

To learn more about function family, here

brainly.com/question/20049838

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