Plz help me fast it a timed test thank you
1 answer:
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Answer:
The correct option is A) 3 square inches; .
Step-by-step explanation:
It is given that the length of the frame is (2x-3) and the width is (x-2)
The area of the rectangle is:
Where, A is the area l is the length and w is the width of the rectangle.
Put and
in the area of the rectangle.
The area of the frame expressed as a polynomial is .
Now substitute x=3 in .
The area of the frame is 3 square inches.
Hence, the correct option is A) 3 square inches; .
Consider right triangle ΔABC with legs AC and BC and hypotenuse AB. Draw the altitude CD.
1. Theorem: The length of each leg of a right triangle is the geometric mean of the length of the hypotenuse and the length of the segment of the hypotenuse adjacent to that leg.
According to this theorem,
Let BC=x cm, then AD=BC=x cm and BD=AB-AD=3-x cm. Then
Take positive value x. You get
2. According to the previous theorem,
Then
Answer:
This solution doesn't need CD=2 cm. Note that if AB=3cm and CD=2cm, then
This means that you cannot find solutions of this equation. Then CD≠2 cm.