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Fofino [41]
2 years ago
12

A rectangle has an area of 24 square inches. The rectangle is reduced by a scale factor of 1/2 . What is the area of the new rec

tangle?
Mathematics
1 answer:
krek1111 [17]2 years ago
4 0

Answer:

12

Step-by-step explanation:

24 x 1/2 = 12

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How can the associative property be used to mentally solve 48+82?
Lilit [14]
(40+80) + (8+2)
120+10
130
your answer would be 130
you group 40 and 80 and get the answer and then group 8 and 2
get answer to both then and then you add them together for the answer
5 0
3 years ago
What is number 3 please explain for brainlest answer !! :))
Phoenix [80]

Answer:

The answer is B) 1/25

Step-by-step explanation:

This is because given that f(x) = 5^x

Hence, f(-2) would be 5^-2, which is equal to (1/5^2) => 1/25

Because a^-b can be written as 1/a^b

6 0
3 years ago
Please answer this question now
lidiya [134]

Answer:

C = (2,2)

Step-by-step explanation:

B = (10 ; 2)

M = (6 ; 2)

C = (x ; y )

|___________|___________|

B (10;2)            M (6;2)             C ( x; y)

So:

dBM = dMC

√[(2-2)^2 + (6-10)^2] = √[(y-2)^2 + (x - 6)^2]

(2-2)^2 - (6-10)^2 = (y-2)^2 + (x - 6)^2

0 + (-4)^2 = (y-2)^2 + (x - 6)^2

16 = (y-2)^2 + (x - 6)^2

16 - (x - 6)^2 = (y-2)^2

Also:

2*dBM = dBC

2*√[(2-2)^2 + (6-10)^2] = √[(y-2)^2 + (x - 10)^2]

4*[(0)^2 + (-4)^2] = (y-2)^2 + (x - 10)^2

4*(16) = (y-2)^2 + (x - 10)^2

64 = (y-2)^2 + (x - 10)^2

64 = 16 - (x - 6)^2 + (x - 10)^2

48 = (x - 10)^2 - (x - 6)^2

48 = x^2 - 20*x + 100 - x^2 + 12*x - 36

48 = - 20*x + 100 + 12*x - 36

8*x = 16

x = 2

Thus:

16 - (x - 6)^2 = (y-2)^2

16 - (2 - 6)^2 = (y-2)^2

16 - (-4)^2 = (y-2)^2

16 - 16 = (y-2)^2

0 =  (y-2)^2

0 = y - 2

2 = y

⇒ C = (2,2)

4 0
3 years ago
Factor Completely: 100x2 - 1
fredd [130]

Answer:

d

Step-by-step explanation:

100x² - 1 ← is a difference of squares and factors in general as

a² - b² = (a - b)(a + b), thus

100x² - 1

= (10x)² - 1²

= (10x - 1)(10x + 1) → d

3 0
3 years ago
Scientists modeled the intensity of the sun, I, as a function of the number of hours since 6:00 a.m., h, using the
MAVERICK [17]

The functions are illustrations of composite functions.

<em>The soil temperature at 2:00pm is 67</em>

The given parameters are:

\mathbf{I(h) =\frac{12h - h^2}{36}} ---- the function for sun intensity

\mathbf{T(I) =\sqrt{5000I}} -- the function for temperature

At 2:00pm, the value of h (number of hours) is:

\mathbf{h = 2:00pm - 6:00am}

\mathbf{h = 8}

Substitute 8 for h in \mathbf{I(h) =\frac{12h - h^2}{36}}, to calculate the sun intensity

\mathbf{I(8) =\frac{12 \times 8 - 8^2}{36}}

\mathbf{I(8) =\frac{32}{36}}

\mathbf{I(8) =\frac{8}{9}}

Substitute 8/9 for I in \mathbf{T(I) =\sqrt{5000I}}, to calculate the temperature of the soil

\mathbf{T(8/9) =\sqrt{5000 \times 8/9}}

\mathbf{T(8/9) =\sqrt{4444.44}}

\mathbf{T(8/9) =66.67}

Approximate

\mathbf{T(8/9) =67}

Hence, the soil temperature at 2:00pm is 67

Read more about composite functions at:

brainly.com/question/20379727

5 0
2 years ago
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