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galina1969 [7]
3 years ago
11

If a function has a verticale asymptote at a certain x-value, then the function is at the value

Mathematics
1 answer:
stiks02 [169]3 years ago
8 0

Answer:

We conclude that If a function has a vertical asymptote at a certain x-value, then the function is undefined at the value.

Step-by-step explanation:

If a function has a vertical asymptote at a certain x-value, then the function is undefined at the value.

For example, let the function

f\left(x\right)\:=\frac{x+3}{x-3}

It is clear that the given function becomes undefined at x = 3 in the denominator.

i.e. 3-3 = 0

It means, the function can not have x = 3, otherwise, the function will become undefined.

In other words, if the function has a vertical asymptote at x = 3, then the function is undefined at the value.

Therefore, we conclude that If a function has a vertical asymptote at a certain x-value, then the function is undefined at the value.

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Help please with this
Anestetic [448]

answer : am/b

Step-by-step explanation:

the rate of copying packets = a/b

each packet (a) contains *m* pages

total number of pages in all books together is =a×m

so the rate of copying of pages = a×m/b

5 0
3 years ago
What is the result of converting 1250 yards into miles? Remember that 1 mile = 1760 yards.
Kobotan [32]

Answer:

Step-by-step explanation:

1.41

8 0
3 years ago
Find the distance between the two points rounding to the nearest tenth (if necessary).
QveST [7]

The distance between two points having coordinates (4, -4) and (9, -2) plotted on the cartesian plane, and rounded to the nearest tenth, will be 5.40 units.

As per the question statement, two points having coordinates (4, -4) and

(9, -2) plotted on the cartesian plane.

We are required to calculate the distance between the above mentioned two points, rounded to the nearest tenth.

To solve this question,  we need to know the Distance-formula which goes as,

"The distance between any two points (x₁, y₁) and (x₂, y₂) can be given by √[(x₂ - x₁)² + (y₂ - y₁)²]"

Assuming that [(x₁, y₁) = (4, -4)] and [(x₂, y₂) = (9, -2)], and substituting these values in the above-mentioned distance formula, we get,

√[(9 - 4)² + {(-2) - (-4)}²]

= √[(9 - 4)² + {(-2) + 4}²]

= √[(9 - 4)² + (4 - 2)²]

=√[(5)² + (2)²]

=√(25 + 4)

=√29

= 5.38 units.

Therefore, rounding (5.38) to the nearest tenth, we get, 5.40.

That is, the distance between two points having coordinates (4, -4) and (9, -2) plotted on the cartesian plane, and rounded to the nearest tenth, will be 5.40 units.

  • Distance: In Mathematics, physics or daily life, distance is a numerical or occasionally qualitative measurement of how far objects or points are from each other.
  • Coordinates: In geometry, coordinates are a pair of numbers that can uniquely determine the position of points or other geometric elements on a Euclidean or Cartesian Plane.

To learn more about Distances and Coordinates, click on the link below.

brainly.com/question/14364020

#SPJ1

5 0
1 year ago
Sarah is a computer engineer and manager and works for a software company. She receives a
daser333 [38]

Answer:

a) Number of projects in the first year = 90

b) Earnings in the twelfth year = $116500

Total money earned in 12 years = $969000

Step-by-step explanation:

Given that:

Number of projects done in fourth year = 129

Number of projects done in tenth year = 207

There is a fixed increase every year.

a) To find:

Number of projects done in the first year.

This problem is nothing but a case of arithmetic progression.

Let the first term i.e. number of projects done in first year = a

Given that:

a_4=129\\a_{10}=207

Formula for n^{th} term of an Arithmetic Progression is given as:

a_n=a+(n-1)d

Where d will represent the number of projects increased every year.

and n is the year number.

a_4=129=a+(4-1)d \\\Rightarrow 129=a+3d .....(1)\\a_{10}=207=a+(10-1)d \\\Rightarrow 207=a+9d .....(2)

Subtracting (2) from (1):

78 = 6d\\\Rightarrow d =13

By equation (1):

129 =a+3\times 13\\\Rightarrow a =129-39\\\Rightarrow a =90

<em>Number of projects in the first year = 90</em>

<em></em>

<em>b) </em>

Number of projects in the twelfth year =

a_{12} = a+11d\\\Rightarrow a_{12} = 90+11\times 13 =233

Each project pays $500

Earnings in the twelfth year = 233 \times 500 = $116500

Sum of an AP is given as:

S_n=\dfrac{n}{2}(2a+(n-1)d)\\\Rightarrow S_{12}=\dfrac{12}{2}(2\times 90+(12-1)\times 13)\\\Rightarrow S_{12}=6\times 323\\\Rightarrow S_{12}=1938

It gives us the total number of projects done in 12 years = 1938

Total money earned in 12 years = 500 \times 1938 = $969000

8 0
2 years ago
183.3 ÷ 0.78=????????????<br> Who ever answers 1st gets brainleist!!!
faust18 [17]

Answer:

235

Step-by-step explanation:

183.3 ÷ 0.78 = 235

This is due to the rules of division.

6 0
3 years ago
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