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3 years ago

1:Krypton gain or lose electrons

Chemistry

1 answer:

vladimir1956 [14]3 years ago

4 0

Answer:

Krypton gain

strontium lose

xenon neither gain or lose

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If i am elemnt #13 (aluminum) how many neutrons do i have?

Rudik [331]

I believe since #13 (aluminum) is in the 13th row you should 13 neutrons. hope this helps :)

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3 years ago

What is the maximum magnification of a compound light microscope?

igor_vitrenko [27]

Answer: 100x

Explanation:

The actual power or magnification of a compound optical microscope is the product of the powers of the ocular (eyepiece) and the objective lens. The maximum normal magnifications of the ocular and objective are 10× and 100× respectively, giving a final magnification of 1,000×.

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3 years ago

Read 2 more answers

2. A 0.5 kg tennis ball has speed of 15m/s. what is the kinetic energy of tennis?

Talja [164]

Explanation:

Given

mass (m) = 0.5 kg

velocity (v) = 15 m/s

Now

Kinetic energy

= 1/2 *m*v²

= 1/2 * 0.5 * 12²

= 0.5 *0.5 * 144

= 36 joule

hope it will help

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3 years ago

What is the energy transformation taking place as a moving roller coaster slowly climbs a steep hill?

Delvig [45]

Kinetic energy to potential energy. Hope this helps.

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3 years ago

A mixture of 14.0 grams of H2, 84.0 grams of N2, and 64.0 grams of O2 are placed in a flask. The partial pressure of the O2 is 7

Hitman42 [59]

Answer:

$P_{tot}=465.27torr$

Explanation:

Hello there!

In this case, according to the given information, it will be possible for us to use the Dalton's law, in order to solve this problem. However, we first need to calculate the mole fraction of oxygen by firstly calculating the moles of each gas:

$n_{H_2}=\frac{14.0g}{2.02g/mol} =6.93mol\\\\n_{N_2}=\frac{84.0g}{28.02g/mol}=3.00mol\\\\n_{O_2}=\frac{64.0}{16.00g/mol} =2.00mol$

Next, we calculate such mole fraction as follows:

$x_{O_2}=\frac{2}{6.93+3+2} =0.168$

Then, given the following equation:

$P_{O_2}=P_{tot}*x_{O_2}$

So we solve for the total pressure as follows:

$P_{tot}=\frac{P_{O_2}}{x_{O_2}} \\\\P_{tot}=\frac{78.00torr}{0.168} \\\\P_{tot}=465.27torr$

Regards!

6 0

3 years ago