The ph of a buffered solution (select all that apply):

Consider the following system at equilibrium:

Vika [28.1K]

Answer:

1) Rightward shift

2) Rightward shift

3) Leftward shift

4) Leftward shift

5) Leftward shift

6) Rightward shift

7) No shift

8) No shift

Explanation:

To evaluate each case we need to consider Le Chatelier's Principle, which states that the adding of additional reactants or products to a system will shift the equilibrium in the opposite direction, to maintain the equilibrium of the system. On the contrary, if we remove a reactant or a product in the system, the equilibrium will be shifted in the direction of the reactant or product reduced, to produce more of it (and thus maintain balance).

Taking into account the above, let's see each statement, in the following equation:

A(aq) + B(aq) ⇄ 2C(aq) (1)

1) Increase A. This will cause a rightward shift in equation 1 in order to consume the reactant added.

2) Increase B. Same as 1), this will cause a rightward in equation 1.

3) Increase C. This will cause a leftward shift in order to consume the excess of product in the system.

4) Decrease A. This will produce a leftward shift to produce the reactant that is being reduced.

5) Decrease B. Same as 4), a leftward shift.

6) Decrease C. This will produce a rightward shift to produce the product that is being reduced.

7) Double A, half B. The double A will cause a rightward shift and the half B will produce a leftward shift, which results in no shift.

8) Double both B and C. Double B will produce a rightward shift and double C will produce the contrary, a leftward shift, so the final result is no shift.

I hope it helps you!

4 0

4 years ago

You find a mysterious white powder in your kitchen. It could be cream of tartar (pH=5), sugar (pH=7), baking soda (pH=8), or dra

GREYUIT [131]

The pH indicators to be used are Phenolphthalein, Red cabbage, Bromthymol blue and Congo red.

<h3>What are pH indicators?</h3>

Indicators are substances which change color as the pH of a medium changes.

The common indicators and their pH range is as follows:

Phenolphthalein - pH range of 8.3 and 10.5
Red cabbage - pH 2 to 10
Bromthymol blue - 6.0 to 7.6
Congo red - 3.0 to 5.2

Therefore, the indicators to be used are Phenolphthalein, Red cabbage, Bromthymol blue and Congo red.

Learn more about pH indicators at: brainly.com/question/13779537

#SPJ1

8 0

2 years ago

A 11.79 g sample of Mo2O3(s) is converted completely to another molybdenum oxide by adding oxygen. The new oxide has a mass of 1

Elis [28]

Answer:

MoO₃

Explanation:

To solve this question we must find the moles of molybdenum in Mo2O3. The moles of Mo remain constant in the new oxide. With the differences in masses we can find the mass of oxygen and its moles obtaining the empirical formula as follows:

<em>Moles Mo2O3 -Molar mass: 239,878g/mol-</em>

11.79g * (1mol / 239.878g) = 0.04915 moles Mo2O3 * (2mol Mo / 1mol Mo2O3) = 0.09830 moles Mo

<em>Mass Mo in the oxides:</em>

0.09830 moles Mo * (95.95g/mol) = 9.432g Mo

<em>Mass oxygen in the new oxide:</em>

14.151g - 9.432g = 4.719g oxygen

<em>Moles Oxygen:</em>

4.719g oxygen * (1mol/16g) = 0.2949 moles O

The ratio of moles of O/Mo:

0.2949molO / 0.09830mol Mo = 3

That means there are 3 moles of oxygen per mole of Molybdenum and the empirical formula is:

3 0

3 years ago

5. A sample of methane has a volume of 225 mL at 0.650 atm of pressure. What will the new volume be if the

Norma-Jean [14]

Answer:

not sure

Explanation:

8 0

3 years ago

1. How many ATOMS of boron are present in 2.20 moles of boron trifluoride ? atoms of boron.

maks197457 [2]

Answer:

1. How many ATOMS of boron are present in 2.20 moles of boron trifluoride? atoms of boron.

2. How many MOLES of fluorine are present in of boron trifluoride? moles of fluorine.

Explanation:

The molecular formula of boron trifluoride is $BF_3$ .

So, one mole of boron trifluoride has one mole of boron atoms.

1. The number of boron atoms in 2.20 moles of boron trifluoride is 2.20 moles.

The number of atoms in 2.20 moles of boron is:

One mole of boron has ---- $6.023x10^2^3$ atoms.

Then, 2.20 moles of boron has

- $=2.20 mol. x 6.023 x 10^2^3 atoms /1 mol\\=13.25x10^2^3 atoms$

2. Calculate the number of moles of BF3 in 5.35*1022 molecules.

$(5.35x10^2^2 molecules/6.023x10^2^3)x 1mol\\=0.0888mol$

One mole of boron trifluoride has three moles of fluorine atoms.

Hence, 0.0888moles of BF3 has 3x0.0888mol of fluorine atoms.

=0.266mol of fluorine atoms.

5 0

3 years ago