Question

On top of a hill, a rocket is launched from a distance 80 feet above a lake. The rocket will fall into the lake after its engine burns out. The rocket's height, h, in feet above the surface of the lake, is given by the equation, h = -16t 2 + 64t + 80, where t is time in seconds. The maximum height of the rocket is
a0 feet.

Answer 1

Answer:

Maximum height is 144 feet.

Step-by-step explanation:

A quadratic equation y =$ax^2+bx+c=0$ gives maximum value when x =$\frac{-b}{2a}$

after finding the value of x we plug value of x in original equation in order to find the maximum value (minimum value in case of a >0)

on comparing given quadratic equation which is variable 't' ,we get a =-16 and  b =64

t =$\frac{-64}{2(-16)}$

plugging this value of t =2 in  original equation in order to get maximum value of h

so h = $\-16(2)^2+16(2)+80$

which gives h =144 feet

Answer 2

Are you trying to find the maximum height? The time it will be to reach the maximum height? I'm pretty confused at what you need help with right now