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Blababa [14]
3 years ago
15

Helppppppppppp again ! Pls

Mathematics
2 answers:
galina1969 [7]3 years ago
6 0
7 pls brainliest me have a good day
adell [148]3 years ago
4 0
7. on the graph when x is at 1, there is a point above it at 7. The point is (-1,7)
You might be interested in
What is the value of x?
AfilCa [17]

Answer:

29

Step-by-step explanation:

7 0
3 years ago
Can u guys help me please
vesna_86 [32]
1.) 25%
2.) 75%
3.) 25
5 0
3 years ago
Find the equation of a line that passes through the point (2,-5) and is perpendicular to the y-axis. Do not put any spaces in yo
Allushta [10]

Answer:

<em>y=-5</em>

Step-by-step explanation:

<u>Equation of the line</u>

Lines can be expressed in several forms. The slope-intercept form of the line is:

y = mx + b

Where m is the slope of the line and m is the y-intercept.

If the line is perpendicular to the y-axis, then it's a horizontal line. Horizontal lines have slope m=0, thus, the equation is:

y = b

To find the value of b, just substitute the given point:

-5=b

The equation of the line is:

y=-5

3 0
3 years ago
How to solve it and why
RideAnS [48]
6.

4x^2 + 4 = 0

Divide both sides by 4

x^2 + 1 = 0

Use the quadratic formula since this cannot be factored.

x = (-b +- sqrt(b^2 - 4ac))/(2a)

x = +- sqrt(-4(1)(1))/2

x = +- sqrt(-4)/2

x = +- 2i/2

x = +- i

x = i or x = -i

Quicker solution:

If you have x^2 = number, then

x = +- sqrt(number)

Once you get to

x^2 + 1 = 0

Subtract 1 from both sides

x^2 = -1

Apply the quick method

x = +- sqrt(-1)

x = +- i

8.

2x^2 + 50 = 0

Divide both sides by 2

x^2 + 25 = 0

Subtract 25 from both sides

x^2 = -25

Apply quick method

x = +- sqrt(25)

x = +- 5i

x = 5i or x = -5i
3 0
3 years ago
[20points][Precal] Find the cross product of -(3/4)V and (1/2)w if v = &lt;-2, 12, -3&gt; and w = &lt;-7, 4, -6&gt;
Lana71 [14]
\mathbf v=\langle-2,12,-3\rangle=-2\,\vec i+12\,\vec j-3\,\vec k
-\dfrac34\mathbf v=\dfrac32\,\vec i-9\,\vec j+\dfrac94\,\vec k

\mathbf w=\langle-7,4,-6\rangle=-7\,\vec i+4\,\vec j-6\,\vec k
\dfrac12\mathbf w=-\dfrac72\,\vec i+2\,\vec j-3\,\vec k

-\dfrac34\mathbf v\times\dfrac12\mathbf w=\begin{vmatrix}\vec i&\vec j&\vec k\\\frac32&-9&\frac94\\-\frac72&2&-3\end{vmatrix}
=\left((-9)\times(-3)-\dfrac94\times2\right)\,\vec i-\left(\dfrac32\times(-3)-\dfrac94\times\left(-\dfrac72\right)\right)\,\vec j+\left(\dfrac32\times2-(-9)\times\left(-\dfrac72\right)\right)\,\vec k
=\dfrac{45}2\,\vec i-\dfrac{27}8\,\vec j-\dfrac{57}2\,\vec k=\left\langle\dfrac{45}2,-\dfrac{27}8,-\dfrac{57}2\right\rangle
6 0
3 years ago
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