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3 years ago

Help!!!!!!!!!!!!!! PLEASE DONT JUST ANSWER SOMETHING UNRELATED FOR POINTS I NEED HELP

Chemistry

2 answers:

nevsk [136]3 years ago

7 0

Answer:

C4 is ozone, O is oxygen,

Explanation:

Oksanka [162]3 years ago

7 0

NaCl- Sodium Chloride

C4- Butane

O- Oxygen

N2- Dinitrogen

Cl- Chlorine

Cl3- Trichloride?

CO2- Carbon Dioxide

H2O2- Hydrogen Peroxide

NaOH- Sodium Hydroxide

C6H12O6- Fructose

CaCO3- Calcium Carbonate

H2O + NaCl → HCl + NaOH.

HCl-Hydrochloric acid

The ones with food, I can't help with

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Identify the precipitate (if any) that forms when NaCH3COO (also written as NaC2H3O2) and HCl are mixed

babymother [125]

For this item, we will have a double-replacement reaction. This means that the compounds will exchange elements. The balanced chemical reaction is shown below.
NaCH3COO + HCl --> NaCl + CH3COOH
So, what are formed in the reaction is the salt NaCl and the carboxylic acid, acetic acid. Hence, the precipitate formed is the salt NaCl.

5 0

3 years ago

Read 2 more answers

The ionization energies (kJ/mol) of hydrogen, nitrogen, sodium, chlorine, and fluorine are 1,312, 1,402, 496, 1,256, and 1,681,

Norma-Jean [14]

Answer: Sodium will most likely to become a monoatomic ion with fluorine when these atoms interact.

Explanation:

Ionization energy is defined as the energy required to remove the most loosely bound electron from a neutral gaseous atom.

With increase in atomic size of the atom, there will be less force of attraction between the nucleus and the valence electrons of the atom. Hence, with lesser amount of energy the valence electrons can be removed.

More is the value of ionization energy more it is difficult to remove an electron. Therefore, lesser is the reactivity of element.

Hence, we can conclude that sodium will most likely to become a monoatomic ion with fluorine when these atoms interact.

6 0

3 years ago

A solution was prepared by dissolving 28.0g of KCL in 225g of water. Part A Calculate the mass percent ofKCL in the solution. Pa

Westkost [7]

Answer:

A. 11.1%

B. 0.0291

C. 1.57 M

D. 1.67 m

Explanation:

Mass of KCl (solute): 28.0 g

Mass of water (solvent): 225 g

Mass of solution: 28.0 g + 225 g = 253 g

The mass percent of KCl is:

%KCl = (mass of KCl/mass of solution) × 100%

%KCl = (28.0 g/253 g) × 100%

%KCl = 11.1%

The molar mass of KCl is 74.55 g/mol. The moles of KCl are:

28.0 g × (1 mol/74.55 g) = 0.376 mol

The molar mass of water is 18.02 g/mol. The moles of water are:

225 g × (1 mol/18.02 g) = 12.5 mol

The total number of moles is 0.376 mol + 12.5 mol = 12.9 mol.

The mole fraction of KCl is:

X(KCl) = moles of KCl / total moles

X(KCl) = 0.376 mol / 12.9 mol

X(KCl) = 0.0291

The volume of the solution is 239 mL (0.239 L).

The molarity of KCl is:

M = moles of KCl / liters of solution

M = 0.376 mol / 0.239 L

M = 1.57 M

The molality of KCl is:

m = moles of KCl / kilograms of solvent

m = 0.376 mol / 0.225 kg

m = 1.67 m

4 0

4 years ago

At the beginning of the reaction: N2 + 3H2 -> 2NH there is 1 mol of N. and 3 moles of H, and at the end of it is present a mi

Nikolay [14]

Answer:

75%

Explanation:

call realistic moles of N2 in the reaction is a

moles of H2 :3a

moles of NH3: 2a

the moles of residual N2 after reaction: 1-a

the moles of residual H2 after react: 3- 3a

the moles of mixture: 2a+1-a+3-3a=2.5

-> a=0.75

H=0.75/1=75%

7 0

3 years ago

Does anyone know the answer to these? Please help.

Phantasy [73]

double replacesment and 1,14,12,6

5 0

4 years ago