M(C2H2O)= 12.0*2 +1.0*2 +16.0 = 42 g/mol is a molar mass for empirical formula.
120.6g/mol/42g/mol ≈ 3
So, empirical formula should be increased 3 times,
and molecular formula is C6H6O3.
Answer is D.
Yeah...it should be out of your system by then
Answer is: gamma emission or gamma decay.
<span>During gamma emission the nucleus emits radiation without changing its composition, if for example have nucleus with six protons and six neutrons (carbon atom) and after gamma decay there is nucleus with six protons and six neutrons.
</span>Gamma rays are the
electromagnetic waves with the shortest wavelengths (1 pm), highest
frequencies (300 EHz) and highest energy (1,24 MeV).
I this is really hard who can help me complete all of these because this is acknowledged
Answer:
0.170 M
Explanation:
As this is a <em>series of dilutions</em>, we can continuosly<em> use the C₁V₁=C₂V₂ formula </em>to solve this problem:
For the first step:
- 59.0 mL * 1.80 M = 258 mL * C₂
Then for when 129 mL of that 0.412 M are diluted by adding 183 mL of water:
- V₂ = 129 mL + 183 mL = 312 mL
Using <em>C₁V₁=C₂V₂:</em>
- 129 mL * 0.412 M = 312 mL * C₂