Answer:
Volume of gold is 9.64 L
.
Explanation:
Given data:
Mass of gold = 85 g
Temperature = standard = 273 K
Pressure = standard = 1 atm
Volume of gold = ?
Solution:
The given problem will be solve by using general gas equation,
PV = nRT
P= Pressure
V = volume
n = number of moles
R = general gas constant = 0.0821 atm.L/ mol.K
T = temperature in kelvin
Now we will calculate the number of moles of gold.
Number of moles = mass/molar mass
Number of moles = 85 g/ 197 g/mol
Number of moles = 0.43
1 atm × V = 0.43 mol ×0.0821 atm.L/ mol.K × 273 K
V = 9.64 atm.L / 1 atm
V = 9.64 L
Radiowave, microwave, infrared radiation
Volume = 3 cm × 3cm × 3cm
= 27 cm ³
Mass = 213 g
Density =
= <span>
</span>
<span> = 7.89 g / cm³
Thus answer is D.</span>
Answer:
Given the following list of densities, which materials would float in a molten vat of lead provided that they do not themselves melt?
Densities (g/mL): lead = 11.4, glass = 2.6, gold = 19.3, charcoal = 0.57, platinum = 21.4.
glass and charcoal
Explanation:
The density of molten lead is about 10.65Kg/m^3
By Archimedes principles, the buoyancy of an object in a fluid is proportional to the mass of fluid displaced
which in turn is proportional to the object's density
Generally an object well float when placed on a denser medium
glass =2.6, and charcoal =0.57 are both less dense so they will float on Lead
Answer:
2 moles
Explanation:
number of mole =mass /molar mass
mass=36
molar mass=(2*1)+16=18
therefore, no of mole =36÷18 =2
