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victus00 [196]
3 years ago
12

Five ice cream parlors out of 10 ice cream parlors were chosen to check the taste of

Mathematics
1 answer:
anastassius [24]3 years ago
6 0

Answer:

no answer.

Step-by-step explanation:

you showed 1 part of the question, add more please.

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In the table, the relation (x, y) is not a function if the missing value of x is___.
stepladder [879]
X is 6 that is the missing value in the equation

8 0
3 years ago
What is the inverse of the function f(x)= 6x-5/x+9
Goshia [24]

Answer:

Inverse of -5-9x/x-6

Step-by-step explanation:

Steps:

1: Interchange the variables x and y.      

x=6y-5/y+9

2: Solve x = 6y-5/y+9 for y

3: Multiply both sides by y+9

4: Simplify and Expand

5: Subtract 9x from both sides.

6: Simplify and Subtract y from both sides then Simplify again

7: Divide both sides by x-6

Answer: Inverse of -5-9x/x-6

<em><u>Hope this helps.</u></em>

6 0
3 years ago
Read 2 more answers
Both the La Plata river dolphin (Pontoporia blainvillei) and
Citrus2011 [14]

Answer:

<em>1. A sperm whale is </em><em>3</em><em> </em><em>orders of magnitude</em><em> heavier than a La Plata river dolphin; 2. The radius of the larger ball is </em><em>one (1) order of magnitude</em><em> bigger than the radius of the smaller ball; 3. The volume of the larger ball is </em><em>3 orders of magnitude</em><em> bigger than the volume of the smaller ball</em>.

Step-by-step explanation:

If we expressed a number as:

\\ N = a * 10^{b} (1)

Where

\\ \frac{1}{\sqrt{10}} \leq a < \sqrt{10} (2)

or

\\ 1 \leq a < 10 (3)

Then, <em>b</em> represents the <em>order of magnitude </em>of such a number (<em>Order of magnitude (2020), </em>in Wikipedia).

The order of magnitude can be defined as "...the smallest power of ten needed to represent a quantity" (Weisstein, Eric W. "Order of Magnitude". From MathWorld--A Wolfram Web Resource).

Having gathered all this information, we can proceed as follows:

<h3>First case</h3>

The<em> La Plata river dolphin</em> weighs between 30 and 50kg and the sperm whale weighs between 35,000 and 40,000kg.

Then, considering (1) and (3) to express the dolphin and whale's weight (since in this way the order of magnitude is the same as the exponent part in the <em>scientific notation</em>):

\\ 30kg \leq Dolphin_{weight} \leq 50kg

\\ 3*10^{1}kg \leq Dolphin_{weight} \leq 5*10^{1}kg

\\ 35000kg \leq Whale_{weight} \leq 40000kg

\\ 3.5*10^{4}kg \leq Whale_{weight} \leq 4.0*10^{4}kg

Since the range for the weights are in the same order of magnitude for both dolphin and whale (considering the definition above):

\\ Dolphin_{weight} = 10^{1}\;(order\;of\;magnitude=1)

\\ Whale_{weight} = 10^{4}\;(order\;of\;magnitude=4)

Then

\\ \frac{Whale_{weight} = 10^{4}}{Dolphin_{weight} = 10^{1}}

\\ \frac{Whale_{weight}}{Dolphin_{weight}} = \frac{10^{4}}{10^{1}}

\\ \frac{Whale_{weight}}{Dolphin_{weight}} = 10^{4-1}

\\ \frac{Whale_{weight}}{Dolphin_{weight}} = 10^{3}

Thus

<em>A sperm whale is </em><em>3</em><em> </em><em>orders of magnitude</em><em> heavier than a La Plata river dolphin.</em>

<h3>Second case</h3>

Following the same reasoning, we can conclude that <em>the radius of the larger ball is </em><em>one (1) order of magnitude</em><em> bigger than the radius of the smaller ball:</em>

\\ \frac{Larger\;ball_{radius}}{Smaller\;ball_{radius}} = \frac{10^{1}}{10^{0}}

\\ \frac{Larger\;ball_{radius}}{Smaller\;ball_{radius}} = 10^{1-0} = 10^{1}

<h3>Third case</h3>

For this case, we need to calculate <em>the volume of a sphere</em> for both radii (1cm and 10cm).

The volume of a sphere is

\\ V_{sphere} = \frac{4}{3}*\pi*R^{3}

Then, the volume of the <em>ball of radius 1cm</em> is:

\\ V_{radius=1} = \frac{4}{3}*\pi*(1cm)^{3}

\\ V_{radius=1} \approx 4.19*10^{0}cm^{3}

And, the volume of the <em>ball of radius 10cm</em> is:

\\ V_{radius=10} = \frac{4}{3}*\pi*(10cm)^{3}

\\ V_{radius=10} \approx 4.19*10^{3}cm^{3}

Thus

\\ \frac{10^{3}}{10^{0}} = 10^{3}

As a result, <em>the volume of the larger ball is </em><em>3 orders of magnitude</em><em> bigger than the volume of the smaller ball</em>.

4 0
3 years ago
If f(x) = x2 - 1 and g(x) = 2x - 3, what is the domain of (fog)(x)?
ladessa [460]

Answer:

domain will be ( -∞, ∞)

Step-by-step explanation:

The given functions are f(x) = x² - 1 and g(x) = 2x - 3

We have to find domain of (fog)(x)

We will find the function (fg)(x) first.

(fog)(x) = f[g(x)]

         = (2x - 3)²

         = 4x² + 9 - 12x - 1

        = 4x² - 12x + 8

       = 4 (x² - 3x + 2)

The given function is defined for all values of x.

Therefore, domain will be ( -∞, ∞)

<u>brainly.com/question/2458431</u>

4 0
2 years ago
Suppose a basketball player has made 291 out of 389 free throws. If the player makes the next 2 free throws, I will pay you $38.
VMariaS [17]

Answer:

The expected value of the proposition is -$0.76.

Step-by-step explanation:

It is provided that a basketball player has made 291 out of 389 free throws.

Then rate of him making a free throw is,

P(\text{free throw})=\frac{291}{389}=0.7481

The probability that he makes the next 2 free throws is:

P(\text{Next 2 free throws})=(0.7481)^{2}=0.5596

The payout rules are:

  • If the player makes the next 2 free throws, I will pay you $38.
  • Otherwise you pay me $50.

Compute the expected value of the proposition as follows:

Expected value = $38 × P (Makes both) + (-$50) × P (Misses both)

                          =($38\times 0.5596)+(-$50\times (1-0.5596))\\=21.2648-22.02\\=-0.7552\\\approx -$0.76

Thus, the expected value of the proposition is -$0.76.

5 0
3 years ago
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