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3 years ago

PLEASE HURRY!!! 30 POINTS, WILL GIVE BRAINLIEST

Mathematics

2 answers:

Gre4nikov [31]3 years ago

5 0

Answer (predicted):

About 0.221

dsp733 years ago

4 0

0.221 should be that answer

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Solve for x. See picture for full problem. Please and thank you!

Nadya [2.5K]

Answer:

x = 16

Step-by-step explanation:

All 3 right triangles are similar, so the lengths of corresponding sides are in proportion.

8√3 / 12 = x / 8√3

12x = (8√3)²

12x = 64 × 3

4x = 64

x = 16

8 0

2 years ago

the box office at the theaters started with $50 in their money till.After selling tickets for $8 each, they had $1,450. To have

Westkost [7]

25 tickets $1400 ÷ 8 =175, 200 -175= 25 tickets

8 0

3 years ago

Find the product of 4cis (pi/4) times 5cis (pi/6) in polar form.

KengaRu [80]

We have the following expression

$4\cdot\text{cis(}\frac{\pi}{4})\cdot5\text{cis(}\frac{\pi}{6})$

This is equivalent to

$4\cdot\text{cis(}\frac{\pi}{4})\cdot5\text{cis(}\frac{\pi}{6})=(4\times5)cis(\frac{\pi}{4}+\frac{\pi}{6})$

Since

$\frac{\pi}{4}+\frac{\pi}{6}=\frac{6\pi+4\pi}{24}=\frac{10}{24}\pi=\frac{5}{12}\pi$

we have that

$4\cdot\text{cis(}\frac{\pi}{4})\cdot5\text{cis(}\frac{\pi}{6})=20cis(\frac{5\pi}{12})$

Therefore, the answer is the second option from top to bottom.

3 0

1 year ago

1. Write the standard form of the line that passes through the given points. (7, -3) and (4, -8)

Sveta_85 [38]

Answer:

1. $-5x+3y+44=0$

2. $2x+y-2=0$

3. $2x+y-4=0$

Step-by-step explanation:

Standard form of a line is $Ax+By+C=0$ .

If a line passing through two points then the equation of line is

$y-y_1=m(x-x_1)$

where, m is slope, i.e., $m=\dfrac{y_2-y_1}{x_2-x_1}$ .

The line passes through the points (7,-3) and (4,-8). So, the equation of line is

$y-(-3)=\dfrac{-8-(-3)}{4-7}(x-7)$

$y+3=\dfrac{-5}{-3}(x-7)$

$y+3=\dfrac{5}{3}(x-7)$

$3(y+3)=5(x-7)$

$3y+9=5x-35$

$-5x+3y+9+35=0$

$-5x+3y+44=0$

Therefore, the required equation is $-5x+3y+44=0$ .

We need to find the equation of the line, in standard form, that has a y-intercept of 2 and is parallel to $2 x + y =-5$ .

Slope of the line : $m=\dfrac{-\text{Coefficient of x}}{\text{Coefficient of y}}=\dfrac{-2}{1}=-2$

Slope of parallel lines are equal. So, the slope of required line is -2 and it passes through the point (0,2).

Equation of line is

$y-2=-2(x-0)$

$y-2=-2x$

$2x+y-2=0$

Therefore, the required equation is $2x+y-2=0$ .

We need to find the equation of the line, in standard form, that has an x-intercept of 2 and is parallel to $2x + y =-5$ .

From part 2, the slope of this line is -2. So, slope of required line is -2 and it passes through the point (2,0).

Equation of line is

$y-0=-2(x-2)$

$y=-2x+4$

$2x+y-4=0$

Therefore, the required equation is $2x+y-4=0$ .

5 0

3 years ago

BRAINLIEST for whoever gets this correct!

ratelena [41]

Answer:

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers