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igomit [66]
2 years ago
7

PLEASE HURRY!!! 30 POINTS, WILL GIVE BRAINLIEST

Mathematics
2 answers:
Gre4nikov [31]2 years ago
5 0

Answer (predicted):

About 0.221

dsp732 years ago
4 0
0.221 should be that answer
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Prove 2^n > n for all n equal to or greater than 1. I mostly need help with how to solve the problem when it is greater than
noname [10]
If n is an integer, you can use induction. First show the inequality holds for n=1. You have 2^1=2>1, which is true.

Now assume this holds in general for n=k, i.e. that 2^k>k. We want to prove the statement then must hold for n=k+1.

Because 2^k>k, you have

2^{k+1}=2\times2^k>2k

and this must be greater than k+1 for the statement to be true, so we require

2k>k+1

for k>1. Well this is obviously true, because solving the inequality gives 3k>1\implies k>\dfrac13. So you're done.

If you n is any real number, you can use derivatives to show that 2^n increases monotonically and faster than n.
7 0
3 years ago
Which is the third greatest rational number
patriot [66]
The order is -1.4, -3/5, 1/4, 0.9, and 9/2. So
D is the correct answer
7 0
3 years ago
PLEASE HELP ASAP
Kaylis [27]

Answer:

11.1

Step-by-step explanation:

6 0
3 years ago
14x - 6 - 7x + 10 = -17
Luden [163]
X equals -3. if you need the steps just search up the equation!
4 0
2 years ago
Read 2 more answers
Look at picture plz help I’m dumb
elena-14-01-66 [18.8K]

Answer: The correct answer is D

 

Step-by-step explanation: you have to factor the polynomial


6 0
3 years ago
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