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lutik1710 [3]
11 months ago
5

Find the product of 4cis (pi/4) times 5cis (pi/6) in polar form.

Mathematics
1 answer:
KengaRu [80]11 months ago
3 0

We have the following expression

4\cdot\text{cis(}\frac{\pi}{4})\cdot5\text{cis(}\frac{\pi}{6})

This is equivalent to

4\cdot\text{cis(}\frac{\pi}{4})\cdot5\text{cis(}\frac{\pi}{6})=(4\times5)cis(\frac{\pi}{4}+\frac{\pi}{6})

Since

\frac{\pi}{4}+\frac{\pi}{6}=\frac{6\pi+4\pi}{24}=\frac{10}{24}\pi=\frac{5}{12}\pi

we have that

4\cdot\text{cis(}\frac{\pi}{4})\cdot5\text{cis(}\frac{\pi}{6})=20cis(\frac{5\pi}{12})

Therefore, the answer is the second option from top to bottom.

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