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lutik1710 [3]
1 year ago
5

Find the product of 4cis (pi/4) times 5cis (pi/6) in polar form.

Mathematics
1 answer:
KengaRu [80]1 year ago
3 0

We have the following expression

4\cdot\text{cis(}\frac{\pi}{4})\cdot5\text{cis(}\frac{\pi}{6})

This is equivalent to

4\cdot\text{cis(}\frac{\pi}{4})\cdot5\text{cis(}\frac{\pi}{6})=(4\times5)cis(\frac{\pi}{4}+\frac{\pi}{6})

Since

\frac{\pi}{4}+\frac{\pi}{6}=\frac{6\pi+4\pi}{24}=\frac{10}{24}\pi=\frac{5}{12}\pi

we have that

4\cdot\text{cis(}\frac{\pi}{4})\cdot5\text{cis(}\frac{\pi}{6})=20cis(\frac{5\pi}{12})

Therefore, the answer is the second option from top to bottom.

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2 years ago
Use the given degree of confidence and sample data to construct a confidence interval for the population proportion p. n = 195,
Semenov [28]
Given:
n = 195, sample size.
x = 162, successes in the sample

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p = x/n = 162/195 = 0.8308

n* p = 195*0.8308 = 162
n*(1-p) = 195*(1 - 0.8308) = 33
If n*p >= 10, and n*(1-p) >= 10, then the sample proportions will have a normal distribution. This condition is satisfied.

The proportion mean is
μ = 0.8308
The proportion standard deviation is
\sigma =  \sqrt{ \frac{p(1-p)}{n} }  = \sqrt{ \frac{0.8308(1-0.8308)}{195} } =0.0269

σ/√n = 0.0269/√195 = 0.00192

At the 95% confidence level, the interval for the population proportion is
(μ - 1.96(σ/√n), μ + 1.96(σ/√n))
= (0.8308 - 1.96*0.00192, 0.8308 + 1.96*0.00192)
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Answer: The 95% confidence interval is (0.827, 0.835)








5 0
3 years ago
Find the volume of material remaining in a hemisphere of radius 2 after a cylindrical hole ofradius 1 is drilled through the cen
lbvjy [14]

Answer:

Step-by-step explanation:

Inicially we have to separate the sphere into 3 parts:

The donut  +  1 ball cap (or a dome) +  the cylinder hole = the Hemisphere

<em>vide picture</em>

As it shows in the picture we have to find the donut.

The donut  = the Hemisphere - ( 1 dome +  the cylinder hole)

  • The hemisphere = \frac{4*pi*r^{3} }{6} (from the hemisphere formula)
  • 1 dome* = \frac{1}{6}*pi*(r-\sqrt{(r^{2} -a^{2}})*(3a^{2}+((r-\sqrt{(r^{2} -a^{2}})^{2} )
  • cylinder hole = pi*a^{2}*h   = pi*a^{2} *(2r - 2*(r-\sqrt{(r^{2} -a^{2}})) (h: cylinder height)

D = \frac{4*pi*r^{3} }{6} - (\frac{1}{6}*pi*(r-\sqrt{(r^{2} -a^{2}})*(3a^{2}+((r-\sqrt{(r^{2} -a^{2}})^{2}  )+ pi*a^{2}*(2r - 2*(r-\sqrt{(r^{2} -a^{2}})) }

D = \frac{4*pi*2^{3} }{6} - (\frac{1}{6}*pi*(2-\sqrt{(2^{2} -1^{2}})*(3*1^{2}+((2-\sqrt{(2^{2} -1^{2}})^{2}  )+ pi*1^{2}*(2*2 - 2*(2-\sqrt{(2^{2} -1^{2}})) }

By basic algebra we have

D = 5.304

*The dome in the 1st picture is represented by the color orange.Looking into the second picture, the dome formula derivatives from the volume of a dome of a hemisphere. By using the following linear system:

  • triangle_side2 + a2 = r2
  • h + triangle_side = r

6 0
3 years ago
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