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3 years ago

How do you work out this equation?

Mathematics

2 answers:

defon3 years ago

7 0

Step-by-step explanation:

x + y = 3. => y = 3 - x

5x + y = 5x + (3 - x) = 15.

=> 4x + 3 = 15

=> 4x = 12, x = 3.

Therefore y = 3 - (3) = 0.

The solutions are x = 3 and y = 0.

Sergeeva-Olga [200]3 years ago

6 0

Answer:

Step-by-step explanation:

x+y=3

5x+y = 15

I method:

y = 3 - x. substitute this in 2nd equation

5x + (3-x) = 15

5x + 3 - x = 15

4x = 12

x=3

y=0

II method:

subtracting 2nd equation and 1st equation we get

4x +0y = 12

x = 3

y = 0

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Subtract 2+ 3a2 -12ab +4b2 from 1+ 8a2+16ab +2b2

Anvisha [2.4K]

The answer of the following subtraction is 5 $a^{2} -2b^{2} +28ab$

Step-by-step explanation:

As per the question the equation will be

$(1+8a^{2}+16ab+2b^{2} ) - (2+3a^{2} -12ab+4b^{2} )$

To find the subtraction,

The steps are as follow

= $1+8a^{2} +16ab+2b^{2} - 2 -3a^{2} +12ab-4b^{2}$

=1-2 + $8a^{2} -3a^{2} +2b^{2} -4b^{2} +16ab+12ab$

[ we took the variables with same power together]

=5 $a^{2} -2b^{2} +28ab$

Hope it helps you.

3 0

4 years ago

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What are the factors of 2x2 + 3x – 54? Select two options.

Darya [45]

Hello there,

The equation that we have to factor is as follows:

2x² + 3x - 54

In order to factor this we first multiply (-54) by 2 and try to find two factor pairs that can be add up to 3.

For this we would use 12 * -9 which gives you -108 when multiplied and when added you would get 3.

2x² + 12x - 9x -54

2x(x + 6) -9(x +6)

(2x - 9) (x + 6)

Now the factor pairs would be: (2x - 9)(x + 6)

Hope I helped,

Amna

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3 years ago

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Given: circle k(O), m AM=125°, m EF=31°, m∠MAF=75°. Find: m∠AME

Bess [88]

Answer:

58°

Step-by-step explanation:

If m AM=125°, then m∠AOM=125°.

If m∠MAF=75°, then m∠MOF=150° (because central angle MOF subtends on the same arc as inscribed angle MAF).

Thus,

m∠FOA=360°-150°-125°=85°.

If mEF=31°, then m∠EOF=31° (as central angle subtended on the arc EF).

Hence,

m∠EOA=m∠EOF+m∠FOA=31°+85°=116°.

Angle EOA is central angle subtended on arc EA, angle AME is inscribed angle subtended on arc AE, thus

m∠AME=1/2m∠EOA=58°.

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4 years ago

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chubhunter [2.5K]

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3 years ago

V2=u2+2as v 2 = u 2 + 2 a s Where v v is the final velocity (in m/s), u u is the initial velocity (in m/s), a a is the accelerat

allsm [11]

Answer:

<em>Final velocity, v = 21.75 m/s</em>

Step-by-step explanation:

Given that the relation between final velocity, initial velocity, acceleration and distance traveled is expressed as:

$v^2=u^2+2as$

Also, given that:

Initial velocity, u = 9 m/s

Acceleration, a = 7 m/ $s^2$

Distance, s = 28 m

To find:

Final velocity, v = ?

Solution:

The given relation between v, u, a and s is:

$v^2=u^2+2as$

We have the values of initial velocity, acceleration and distance traveled in the question statement. We just need to put all these values to find the value of final velocity.

Let us put all the values in the given equation and try to find final velocity, v:

$v^2=9^2+2\times 7 \times 28\\\Rightarrow v^2=81+14 \times 28\\\Rightarrow v^2=81+392\\\Rightarrow v^2=473\\\Rightarrow v=\sqrt{473}\\\Rightarrow v=21.75\ m/s$

So, the answer is:

<em>final velocity, v = 21.75 m/s</em>

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3 years ago