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2 years ago

12

(HELP! MARKING BRAINLIEST) At 2pm, a store had sold 15 packs of toilet paper. By 5pm, the store had sold 57 packs of toilet pape

r. What is the average rate of change?

1 answer:

viktelen [127]2 years ago

5 0

Answer:

14 packs per hour

Step-by-step explanation:

The store sold 57 - 15 = 42 packs of toilet paper in 3 hours.

42 packs in 3 hours = 42/3 = 14 packs per hour

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Please help me on this will give you brainliest!

kirill [66]

Answer:

∠V = 33°

∠W = 90°

∠X = 57°

Step-by-step explanation:

In a right triangle, the sum of the acute angles is 90 degrees

(2x+3) + (3x+12) = 90

combine like terms

5x + 15 = 90

5x = 75

x = 15

∠V = 2x+3, x=15

2(15) + 3

30 + 3

33°

∠X = 3x+12, x=15

3(15) + 12

45 + 12

57°

8 0

3 years ago

Read 2 more answers

Layla has the following data:

ratelena [41]

The answer would be 25 because to find the range you have to subtract the highest number with the lowest number which would be 29-25=4

6 0

3 years ago

Someone please help me im timed

Nikitich [7]

Answer:

C

Step-by-step explanation:

All sides of a square are equal.

3 0

2 years ago

A new test to detect TB has been designed. It is estimated that 88% of people taking this test have the disease. The test detect

Elodia [21]

Answer:

Correct option: (a) 0.1452

Step-by-step explanation:

The new test designed for detecting TB is being analysed.

Denote the events as follows:

<em>D</em> = a person has the disease

<em>X</em> = the test is positive.

The information provided is:

$P(D)=0.88\\P(X|D)=0.97\\P(X^{c}|D^{c})=0.99$

Compute the probability that a person does not have the disease as follows:

$P(D^{c})=1-P(D)=1-0.88=0.12$

The probability of a person not having the disease is 0.12.

Compute the probability that a randomly selected person is tested negative but does have the disease as follows:

$P(X^{c}\cap D)=P(X^{c}|D)P(D)\\=[1-P(X|D)]\times P(D)\\=[1-0.97]\times 0.88\\=0.03\times 0.88\\=0.0264$

Compute the probability that a randomly selected person is tested negative but does not have the disease as follows:

$P(X^{c}\cap D^{c})=P(X^{c}|D^{c})P(D^{c})\\=[1-P(X|D)]\times{1- P(D)]\\=0.99\times 0.12\\=0.1188$

Compute the probability that a randomly selected person is tested negative as follows:

$P(X^{c})=P(X^{c}\cap D)+P(X^{c}\cap D^{c})$

$=0.0264+0.1188\\=0.1452$

Thus, the probability of the test indicating that the person does not have the disease is 0.1452.

4 0

3 years ago

Please answer 3-6 and show work

GuDViN [60]

Answer:

3. 10 - 5 is 5. so that is the difference. difference means subtraction.

4. 108 - 30 = 78. so she can move 78 degrees miore after therapy because 108 minues 30 is 78

5. 99 because 180 - 81 = 99. there is always 180 degrees in a line angle.

6. 130 degrees. 25 + 25 = 50 so 180 minus 50 equals 130

Step-by-step explanation:

8 0

3 years ago