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Varvara68 [4.7K]
3 years ago
10

You may need to use the appropriate technology to answer this question.

Mathematics
1 answer:
kirill115 [55]3 years ago
6 0

Answer:

H0: Having health insurance is independent of the size of the company.

Ha: Having health insurance is not independent of the size of the company.

χ²= 9.284

The corresponding p-value for the test is  = 0.0096

Reject H0. We conclude health insurance coverage is not independent of the size of the company.

For small companies, 40% do not provide health insurance. For medium companies, 11.4% do not provide health insurance. For large companies,18 % do not provide health insurance.

These percentages support the conclusion that small companies are less more equally likely to provide health insurance coverage when compared to medium and large companies.

Step-by-step explanation:

       small medium large Total

yes      30         59         82              171

no       20            16        18             54

Total: 50             75       100        225

Expected Values      small         medium       large          Total

yes { 50* 171/225} = 38                   57                76         171

<u>no                                 12               18                   24              54</u>

<u>Total                   50                      75            100                     225  </u>

<u>Squared Distances                small           medium            large</u>

yes                     {(30 - 38)^2}/38

                                          = 1.684                 0.07              0.474

no                      {(20 - 12)^2} /12

                                      = 5.333                   0.22                 1.5

1) The  null and alternative hypotheses can be formulated as

H0: Having health insurance is independent of the size of the company.

Ha: Having health insurance is not independent of the size of the company.

(2) the significance level is alpha =0.05 ,

the number of degrees of freedom is df = (2 - 1) * (3 - 1) = 2df

so then the rejection region for this test is  χ 2 :χ 2 >5.991.

3) Test Statistics under H0 is

χ²= ∑ (O - E)²/ E where O is the observed and E is the expected frequency

4) χ²= 1.684+5.333+0.07+0.222+0.474+1.5

= 9.284

Since it is observed that χ²=9.284 >χ²= 5.991  it is concluded that the null hypothesis is rejected.

5) Conclusion

It is concluded that the null hypothesis H0 is rejected. Therefore, there is not enough evidence to claim that the two variables are dependent at 0.05 significance level.

The corresponding p-value for the test is  = 0.0096

b)  The percentages of

Small %= 20/50= 0.4= 40%

Medium %= 16/75 = 0.786= 11.4%

Large %= 18/100= 0.18= 18%

For small companies, 40% do not provide health insurance. For medium companies, 11.4% do not provide health insurance. For large companies,18 % do not provide health insurance.

These percentages support the conclusion that small companies are less more equally likely to provide health insurance coverage when compared to medium and large companies.

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