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3 years ago

What's the greatest common factor of 8, 44, and 12

Mathematics

1 answer:

lubasha [3.4K]3 years ago

8 0

Answer:

Step-by-step explanation:

the greatest common factor of 8,44,12 is 4

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8. Divide: (6x² - 4x)+2x A. 3x - 4x B. 3x - 2x C. 6x-2 D. 3x - 2

kompoz [17]

Answer:

3x-2

Step-by-step explanation:

I think you meant (6x^2-4x) divided by 2x

if it isn't then pls comment what you meant

8 0

3 years ago

Mary sold 147 bags of popcorn in 3 days. At this rate, how many bags of popcorn will Mary sell in 5 1/2 days?

lord [1]

Answer:

147bags=3days

?bags=5 1/2days

147×11/2

1617÷3

1617×1

2 3

=539/2

=269 1/2 bags or 269.5bags

5 0

3 years ago

a six sided number cube has faces with the numbers 1 through 6 marked on them. what is the probability that a number less than 3

Charra [1.4K]

1/3 would be the answer

8 0

3 years ago

What is the answer ?

sergiy2304 [10]

Answer:

First box: 2

Second box: 30

Third box: 42

Step-by-step explanation:

5 sixes means 5 · 6, which equals 30. An unknown amount of sixes equals 12, which is 2 because 2 · 6 = 12.

30 + 12 = 42

7 · 6 = 42, so 42 is the answer.

I hope this helped! :)

4 0

4 years ago

Read 2 more answers

(1/1+sintheta)=sec^2theta-secthetatantheta pls help me verify this

Xelga [282]

Answer:

See Below.

Step-by-step explanation:

We want to verify the equation:

$\displaystyle \frac{1}{1+\sin\theta} = \sec^2\theta - \sec\theta \tan\theta$

To start, we can multiply the fraction by (1 - sin(θ)). This yields:

$\displaystyle \frac{1}{1+\sin\theta}\left(\frac{1-\sin\theta}{1-\sin\theta}\right) = \sec^2\theta - \sec\theta \tan\theta$

Simplify. The denominator uses the difference of two squares pattern:

$\displaystyle \frac{1-\sin\theta}{\underbrace{1-\sin^2\theta}_{(a+b)(a-b)=a^2-b^2}} = \sec^2\theta - \sec\theta \tan\theta$

Recall that sin²(θ) + cos²(θ) = 1. Hence, cos²(θ) = 1 - sin²(θ). Substitute:

$\displaystyle \displaystyle \frac{1-\sin\theta}{\cos^2\theta} = \sec^2\theta - \sec\theta \tan\theta$

Split into two separate fractions:

$\displaystyle \frac{1}{\cos^2\theta} -\frac{\sin\theta}{\cos^2\theta} = \sec^2\theta - \sec\theta\tan\theta$

Rewrite the two fractions:

$\displaystyle \left(\frac{1}{\cos\theta}\right)^2-\frac{\sin\theta}{\cos\theta}\cdot \frac{1}{\cos\theta}=\sec^2\theta - \sec\theta \tan\theta$

By definition, 1 / cos(θ) = sec(θ) and sin(θ)/cos(θ) = tan(θ). Hence:

$\displaystyle \sec^2\theta - \sec\theta\tan\theta \stackrel{\checkmark}{=} \sec^2\theta - \sec\theta\tan\theta$

Hence verified.

8 0

3 years ago

What's the greatest common factor of 8, 44, and 12​

What's the greatest common factor of 8, 44, and 12