Answer:
part A :BODMAS ( Bracket of Division Multiplication Addition Subtraction )
part b; Bracket (2+3.2) = - 2- 3.2
= 16- 2-3.2 +30-5
ADDITION:-3.2+30 = - 33.2
16-2(-33.2)30-5
14-33.2 +30-5
14-33.2 +25
-19.2+25
-44.2
Step-by-step explanation:
THE FOLLOWING EQUATION CAN ONLY BE SOLVED USING BODMAS
You can use this formula <span>P(AorB) = P(A) + P(B) - P(AandB)
Given:
35 LG (14 F & 21 M)
44 SB (28 F & 16 M)
Req:
- the probability that it is a female (F) or a sky blue (SB)
Sol:
</span>P(F or SB) = P(F) + P(SB) - P(F and SB)
= [(14 F + 28 F)/(35 + 44)] + [(44 SB)/(35 + 44)] - [(28 F)/(35 + 44)]
= 53.16 + 55.70 - 35.44
= 73.42%
You have to deduct 28 female parakeets from 44 sky blue parakeets because the 28 parakeets are already accounted for in the female parakeets. You can also think of how many ways you can choose a female parakeet and a sky blue parakeet. Add all female parakeets (14 + 28) = 42. Sky blue parakeet equaled to 44. Minus the 28 female parakeets included in the sky blue parakeet to avoid double counting. 42 + 44 - 28 = 58 divided by 79 (35 + 44) total parakeets = 73.42%
Answer:
23
Step-by-step explanation:
Answer:
15 
Step-by-step explanation:
Given:
Volume of Cone= 5 
Solution:
Formula:
Volume of Cone =
Volume of Cylinder= 
We can say that
Volume of Cone = 
Volume of Cylinder
Volume of cylinder = 3 
Volume of Cone
Now Substituting given data we get
Volume of Cylinder= 35
Volume of Cylinder= 15 
