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3 years ago

64.8=6(m+2.9) what is m please help me and explain how did you get your answer

Mathematics

2 answers:

tigry1 [53]3 years ago

8 0

The answers is
M=7.9

BabaBlast [244]3 years ago

4 0

Answer:

= −11.2

Step-by-step explanation:

64.8=6(m+22)

We move all terms to the left:

64.8-(6(m+22))=0

We calculate terms in parentheses: -(6(m+22)), so:

6(m+22)

We multiply parentheses

6m+132

Back to the equation:

-(6m+132)

We get rid of parentheses

-6m-132+64.8=0

We add all the numbers together, and all the variables

-6m-67.2=0

We move all terms containing m to the left, all other terms to the right

-6m=67.2

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Step-by-step explanation:

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3 years ago

NEED ANSWERS ASAP, 100 POINTS! There are twenty classes at each of two middle schools. The number of students in each class at e

DiKsa [7]

Note: You missed to add the dot plots chart. As I found the chart after a little research. Thus, I am attaching it and based on that dot plot chart I am solving the question which anyways would clear you concept.

Answer:

'There are about 2 more students in each class at Oak Middle School than at Poplar Middle School' is the correct statement.

Step-by-step explanation:

From the diagram, it is clear that

The data set containing Poplar Middle School:

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The mean of a data set is the sum of the terms divided by the total number of terms. Using math notation we have:

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$=\frac{87}{4}$

$= 21.75$

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5 0

3 years ago

The function f(x)=Acosh(Cx)+Bsinh(Cx). I need help determining the value of constant C>0 when the second derivative f''(x)=25

Rus_ich [418]

Answer:

C = 5.

Step-by-step explanation:

First, you need to remember that:

For the function:

h(x) = Sinh(k*x)

We have:

h'(x) = k*Cosh(k*x)

and for the Cosh function:

g(x) = Cosh(k*x)

g'(x) = k*Cosh(k*x).

Now let's go to our problem:

We have f(x) = A*cosh(C*x) + B*Sinh(C*x)

We want to find the value of C such that:

f''(x) = 25*f(x)

So let's derive f(x):

f'(x) = A*C*Sinh(C*x) + B*C*Cosh(C*x)

and again:

f''(x) = A*C*C*Cosh(C*x) + B*C*C*Sinh(C*x)

f''(x) = C^2*(A*cosh(C*x) + B*Sinh(C*x)) = C^2*f(x)

And we wanted to get:

f''(x) = 25*f(x) = C^2*f(x)

then:

25 = C^2

√25 = C

And because we know that C > 0, we take the positive solution of the square root, then:

C = 5

6 0

3 years ago

Which story problem could be solved using the given equation? 1/5×2/3=m

Ksju [112]

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4 years ago

Read 2 more answers

Two vertical poles of lengths 11 ft and 14 ft stand 16 ft apart. A cable reaches from the top of one pole to some point on the g

Alex17521 [72]

We are given

total length of cable is 30 feet

and this cable is on hypotenuse sides of the triangles

so, we can draw triangle as

Let's assume those hypotenuse as 'a' and 'b'

so, we will have

$a+b=30$

now, we can find 'a' and 'b' from triangle

Smaller triangle:

$a=\sqrt{x^2+11^2}$

Larger triangle:

$b=\sqrt{(16-x)^2+14^2}$

we know that

$a+b=30$

so, we can plug this value

and we get

$\sqrt{x^2+11^2}+\sqrt{(16-x)^2+14^2} =30$

now, we can solve for x

$\left(\sqrt{x^2+11^2}\right)^2=\left(30-\sqrt{\left(16-x\right)^2+14^2}\right)^2$

$32x-1231=-60\sqrt{x^2-32x+452}$

$1024x^2-78784x+1515361=3600x^2-115200x+1627200$

now, we can use quadratic formula

we get

$x=\frac{-\sqrt{36416^2-1152389056}+36416}{5152},\:x=\frac{\sqrt{36416^2-1152389056}+36416}{5152}$

$x=4.510,x=9.627$

so,

The point should be located 4.510 feet , 9.627 feet from the smaller pole to use 30 feet cable............Answer

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3 years ago