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garik1379 [7]
3 years ago
11

64.8=6(m+2.9) what is m please help me and explain how did you get your answer

Mathematics
2 answers:
tigry1 [53]3 years ago
8 0
The answers is
M=7.9
BabaBlast [244]3 years ago
4 0

Answer:

= −11.2

Step-by-step explanation:

64.8=6(m+22)

We move all terms to the left:

64.8-(6(m+22))=0

We calculate terms in parentheses: -(6(m+22)), so:

6(m+22)

We multiply parentheses

6m+132

Back to the equation:

-(6m+132)

We get rid of parentheses

-6m-132+64.8=0

We add all the numbers together, and all the variables

-6m-67.2=0

We move all terms containing m to the left, all other terms to the right

-6m=67.2

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Your part time job pays you $14/h. You work approximately 12 hours/week.
kirill115 [55]

Answer:

  1. <u>BOX 1 </u>=  672.00

(14 * 12 = 168

168 * 4 = $ 672 )

     2. <u>BOX 2</u> = 282.95

(Cell phone= $45 A MONTH

Eating outside = $50 A MONTH

12 .50 * 4   = 50   (4 WEEKS A MONTH )

Transportation =  131.2 A MONTH

32.80 * 4 = 131.2  (4 WEEKS A MONTH )

Movie =  $16.75 A MONTH

Charity = $ 40 A MONTH

10 * 4  (4 WEEKS A MONTH )

<u> MONTHLY EXPENSE </u> = 45 + 50 + 131.2 + 16.75 + 40

<u> MONTHLY EXPENSE </u> = 282.95 )

      3. <u>BOX 3</u> = 389.05

Money that can be saved = Monthly income - Monthly expense

Money that can be saved = 672 -  282.95

                                          = 389.05

<h2><em><u>please give brainliest </u></em></h2>
4 0
3 years ago
Find the angle between the given vector in degrees. u=&lt;6, 4&gt;, v=&lt;7, 5&gt; HELPPPPPPPPPP
Paladinen [302]

Recall that

\vec a\cdot\vec b=\|\vec a\|\|\vec b\|\cos\theta

where \theta is the angle between the vectors \vec a,\vec b whose magnitudes are \|\vec a\|,\|\vec b\|, respectively.

We have

\langle6,4\rangle\cdot\langle7,5\rangle=\sqrt{6^2+4^2}\sqrt{7^2+5^2}\cos\theta

\cos\theta=\dfrac{31}{\sqrt{962}}\implies\theta\approx88.2^\circ

7 0
2 years ago
Factor completely:<br> 3x² + 5x - 12
Paladinen [302]

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7 0
2 years ago
Cydus<br> How many solutions doos the equation 4+4x - 3=4x +5 have?
ipn [44]
0 solutions because simplifying the equation gives us 1 = 5, which is never true
5 0
3 years ago
Read 2 more answers
Find the tangent of the angle in between the lines 2x+3y–5=0 and 5x=7y+3?
tino4ka555 [31]

Answer:

-29/31

Step-by-step explanation:

We are given;

The equations;

2x+3y–5=0 and 5x=7y+3

We are required to determine the tangent of the angle between the two lines;

We need to know that;

When an equation is written in the form of, y = mx + c

Then, tan θ = m , where θ is the angle between the line and the x-axis.

Therefore, we can find the tangent of the angle between each line given and the x-axis.

2x+3y–5=0

we first write it in the form, y = mx + c

We get, y = -2/3x + 5/3

Thus, tan θ₁ = -2/3

5x=7y+3

In the form of y = mx + c

We get; y = 5/7x - 3/7

Thus, tan θ₂ = 5/7

Using the formula, θ = tan^-1((m1-m2)/(1+m1m2)) , where θ is angle between the two lines.

Thus, the tangent of the angle between the two lines will be;

tan θ = ((m1-m2)/(1+m1m2))

        = ((-2/3-5/7)/(1 + (-2/3 × 5/7)))

        = -29/21 ÷ 31/21

        = -29/31

Thus, the tangent of the angle between the two lines is -29/31

7 0
3 years ago
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